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3 years ago

Pls really need help asapppp

Mathematics

1 answer:

Anit [1.1K]3 years ago

8 0

Answer:

105 sq cm

Step-by-step explanation:

The bottom rectangle is 6 x 15 = 90 sq cm

The triangle at the top has a length of 15 - 9 = 6 cm and a height of 11 - 6 = 5 cm.

A triangle is 1/2bh so 1/2 x 6 x 5 = 15 sq cm

Add the areas together

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In AKLM, m = 1.2 cm, k = 5.1 cm and

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Answer:

4.2 cm

Step-by-step explanation:

The law of cosines is applicable.

l² = k² +m² -2km·cos(L)

l² = 5.1² +1.2² -2·5.1·1.2·cos(35°) ≈ 17.4236

l ≈ √17.4236

l ≈ 4.2 . . . cm

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3 years ago

A carpenter has a 6 foot long board, he wants to cut the board into pieces that are 4/5 foot long

Artyom0805 [142]

You need to divide 6 by 4/5.
6÷4/5
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3 years ago

Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.

lakkis [162]

Answer:

$2*sin(x)+y*cos(x)-cos(y)=C_1$

Step-by-step explanation:

Let:

$P(x,y)=2*cos(x)-y*sin(x)$

$Q(x,y)=cos(x)+sin(y)$

This is an exact differential equation because:

$\frac{\partial P(x,y)}{\partial y} =-sin(x)$

$\frac{\partial Q(x,y)}{\partial x}=-sin(x)$

With this in mind let's define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x}=P(x,y)$

and

$\frac{\partial f(x,y)}{\partial y}=Q(x,y)$

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y)

$f(x,y)=\int\ 2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)$

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}$

Now, let's replace the previous result into $\frac{\partial f(x,y)}{\partial y}=Q(x,y)$ :

$cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)$

Solving for $\frac{dg(y)}{dy}$

$\frac{dg(y)}{dy}=sin(y)$

Integrating both sides with respect to y:

$g(y)=\int\ sin(y) \, dy =-cos(y)$

Replacing this result into f(x,y)

$f(x,y)=2*sin(x)+y*cos(x)-cos(y)$

Finally the solution is f(x,y)=C1 :

$2*sin(x)+y*cos(x)-cos(y)=C_1$

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3 years ago

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To know what kind of triangle is it. use the pythagorean theorem:
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Step-by-step explanation:

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3 years ago

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