All categories

3 years ago

(1/3)y2 + 12 = 5x where x = 3

Mathematics

1 answer:

IgorLugansk [536]3 years ago

8 0

If x=3
(1/3)y2+12=15
(1/3)y2=15-12
(1/3)y2=3
y2=3*3
y2=9
y=3

You might be interested in

Jacob and Caden share a reward of $108 in a ratio 7:2. How much does Jacob get?

anyanavicka [17]

1. : 0.286

3.5 : 1.

hope this helps

4 0

3 years ago

Read 2 more answers

4 How many 3-cup servings are in 4 cups? A. 1/2 B. 2/ C. 4 D. 12

anygoal [31]

This questions stated differently so I’m assuming it’s 4?

7 0

1 year ago

Can anyone help with this question

WARRIOR [948]

Answer:

Step-by-step explanation:

4nfhfhs

7 0

3 years ago

-3 + 42 > 3 x > 15 x < 15 x > 13 x < 13

Ilya [14]

Answer:

Where's the x?

I am assuming that the problem must be

-3 + 42 > 3x

if that is true, then

x < 13.

As this statement is, -3 + 42 > 3 is a true statement because -3 + 42 = 39, and

39 > 3 [39 is always greater than 3]

Step-by-step explanation:

Let me know if you need a step by step.

8 0

3 years ago

Read 2 more answers

Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

6 0

3 years ago