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Ivenika [448]
2 years ago
7

How to hack a I'd Indian brainly bot​

Computers and Technology
1 answer:
allsm [11]2 years ago
4 0
Why u wanna hack a Indian bot-
You might be interested in
Write a method body for the static method isDivisibleBy5 shown below. The only NaturalNumber methods you are allowed to use are
raketka [301]

Answer:

public static boolean isDivisibleBy5(int number) {

       boolean isTrue = true;

       if (number % 5 == 0)

           isTrue = true;

       else

           isTrue = false;

           

       return isTrue;

   }

Explanation:

- Create a method called <em>isDivisibleBy5</em> that takes one parameter, an integer number

- Inside the method, create a boolean variable, <em>isTrue</em>, that will be used to store the result

- Check if the number is divisible by 5, using the module operator. If it is, set the isTrue as true. Otherwise, set the isTrue as false

- Return the isTrue

5 0
2 years ago
In your own words explain how to add footer and head in a word doc.
stiks02 [169]

In google docs:

  1. Go to Insert on the Navigation Bar
  2. Go to "Header and Page Number"
  3. Press "Header" or "Footer" depending on your situation

3 0
3 years ago
When an interrogator speaks highly about how a crime was committed, hoping to get the suspect to brag about his or her involveme
Alexeev081 [22]

I’d go with b. egotistical, i’m not entirely sure though. It seems like he is trying to appeal to the suspects EGO

8 0
3 years ago
Read 2 more answers
How many different integers can be represented with a 4-digit number in base 13?
AnnyKZ [126]
That would be 13^4, or 13*13*13*13 = 28561
6 0
3 years ago
Your baby brother has found the hammer and is eagerly eyeing one of the boxes. Describe and analyze an algorithm to determine if
erastovalidia [21]

Answer:

Question is incomplete.

Assuming the below info to complete the question

You have a collection of n lockboxes and m gold keys. Each key unlocks at most one box. Without a matching key, the only way to open a box is to smash it with a hammer. Your baby brother has locked all your keys inside the boxes! Luckily, you know which keys (if any) are inside each box.

Detailed answer is written in explanation field.

Explanation:

We have to find the reachability using the directed graph G = (V, E)

In this V are boxes are considered to be non empty and it may contain key.

Edges E will have keys .

G will have directed edge b1b2 if in-case box b1 will have key to box b2 and box b1 contains one key in it.

Suppose if a key opens empty box or doesn’t contain useful key means can’t open anything , then it doesn’t belongs to any edge.

Now, If baby brother has chosen box B, then we have to estimate for other boxes reachability from B in Graph G.

If and only if all other boxes have directed path from box B then just by smashing box B we can get the key to box b1 till last box and we can unlock those.

After first search from B we can start marking all other vertex of graph G.

So algorithm will be O ( V +E ) = O (n+m) time.

7 0
3 years ago
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