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Ivanshal [37]
2 years ago
12

Which technological tool is important for storing critical files?.

Computers and Technology
1 answer:
Vanyuwa [196]2 years ago
3 0

The technological tools that can be considered important for storing critical files are battery backup systems and drives. These devices can be used to store data and supply energy.

<h3>Battery backup systems</h3>

A home battery backup system is a device used to keep the electrical system working in the event when the electrical source goes down.

In computation, there are three major classes of batteries systems:  Lead-Acid, Nickel-Cadmium, and Lithium-Ion.

An uninterruptible power supply (UPS) can be considered as a battery backup supply capable of charging when the power is on.

Learn more about battery backup systems here:

brainly.com/question/7125266

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Does downloading from mega connect someone to your computer
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The Pentium 4 Prescott processor, released in 2004, has a clock rate of 3.6 GHz and voltage of 1.25 V. Assume that, on average,
Zarrin [17]

Answer:

a) C = 3.2 x 10^-8 F, C = 2.9 x 10^-8 F

b) 10%, 42.86%, 0.11, 0.75

c) 0.849 volts to maintain the same leakage current in the Pentium 4 Prescott Processor. 0.783 Volts to maintain the same leakage current in the Core i5 Ivy Bridge Processor.

Explanation:

<u>For the Pentium 4 Prescott processor:</u>

Clock rate (f) = 3.6 GHz

Voltage (V) = 1.25 V

Static Power Consumption = 10 W

Dynamic Power Consumption = 90 W

<u>For the Core i5 Ivy Bridge processor:</u>

Clock rate (f) = 3.4 GHz

Voltage (V) = 0.9 V

Static Power Consumption (SP) = 30 W

Dynamic Power Consumption (DP) = 40 W

(a) To find the average capacitive loads, use the formula:

DP = (1/2) x C x V² x f

Rearranging:

C = (2 x DP)/(V² x f)

For the Pentium 4 Prescott processor:

C = (2 x 90) / [(1.25)² x 3.6 x 10^9]

C = 3.2 x 10^-8 F

For the Core i5 Ivy Bridge processor:

C = (2 x 40) / [(0.9)² x 3.4 x 10^9]

C = 2.9 x 10^-8 F

(b) Percentage of the total dissipated power comprised by the static power can  be found by the formula:

<u>[Static Power/(Static Power + Dynamic Power)] x 100</u>

For the Pentium 4 Prescott Processor:

[10/(90+10)] x 100  = 10%

For the Core i5 Ivy Bridge Processor:

[30/30+40] x 100 = 42.86 %

Ratio of static power to dynamic power for each technology can be computed as:

Pentium 4 Prescott: 10/90 = 0.11

Core i5 Ivy Bridge: 30/40 = 0.75

(c) The total dissipated power can be calculated by:

P = DP + SP

For Static Power we have the formula:

SP = VI where I is the leakage current.

I = SP/V

For Pentium 4 Prescott: I = 10/1.25 = 8A

For Core i5 Ivy Bridge: I = 30/0.9 = 3.33 A

The total disspited power is reduced by 10%, meaning the ratio of new power to old power must be 90% = 0.9. So,

New Power/Old Power = 0.9

For Pentium 4 Prescott:

DP + SP / 100 = 0.9

VI + CV²F = 0.9 x 100

V(8) + (3.2 x 10^-8)V²(3.6 x 10^9) = 90

8V + 115.2V² - 90 = 0

By solving the quadratic equation, we get the positive answer as 0.849. This means that the voltage should be reduced to 0.849 volts to maintain the same leakage current in the Pentium 4 Prescott Processor.

For Core i5 Ivy Bridge:

DP + SP / 70 = 0.9

V(3.33) + (2.9 x 10^-8)V²(3.4 x 10^9) = 70 x 0.9

3.33V +98.6V² -63 = 0

By solving the quadratic equation we get the positive answer as 0.783. This means that the voltage should be reduced to 0.783 Volts to maintain the same leakage current in the Core i5 Ivy Bridge Processor.

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faltersainse [42]
More features/more space makes things easier to work on and cool down
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