What are the advantage of an e-library

HIPAA protects which of the following kinds of data?

Gelneren [198K]

The answer is a i looked up the question and it says a

5 0

3 years ago

Read 2 more answers

What are the nine tasks (steps) you should perform prior to upgrading a computer to windows 7?

BARSIC [14]

I think those 9 tasks would be :

1. learns windows powershell
2. Plow through licensing
3. focus on strategic improvements
4. Expand the deployment scope
5. Prepare for distributed security
6. Virtualize your destkop
7. Evaluate enterprise features
8. Build compatibility safety nets
9. Remove your users' local admin rights

4 0

4 years ago

Alcatel-Lucent’s High Leverage Network (HLN) increases bandwidth and network capabilities while reducing the negative impact on

Zinaida [17]

Answer:

The networks are intelligent and send packets at the highest speed and most efficiently.

Explanation:

Alcatel-Lucent was founded in 1919, it was a French global telecommunications equipment manufacturing company with its headquarter in Paris, France. Alcatel-Lucent provide services such as telecommunications and hybrid networking solutions deployed both in the cloud and on properties.

Alcatel-Lucent’s High Leverage Network (HLN) increases bandwidth and network capabilities while reducing the negative impact on the environment. This high leverage network can handle large amounts of traffic more efficiently because the networks are intelligent and send packets at the highest speed and most efficiently. HLN are intelligent such that it delivers increased bandwidth using fewer devices and energy.

Generally, when the High Leverage Network (HLN) is successfully implemented, it helps telecommunications companies to improve their maintenance costs, operational efficiency, enhance network performance and capacity to meet the bandwidth demands of their end users.

7 0

3 years ago

C++ code only

nordsb [41]

Using the computational language C++ it is possible to write a code is possible to create a function that stores items like this:

<h3>Writting the code in C++: </h3>

//Header files

#include <iostream>

#include <string>

#include <fstream>

using namespace std;

//Class inventoryItem

class inventoryItem

{

public:

//Variable declaration

string itemName;

string itemNumber;

double itemPrice;

int itemQuantity;

};

//implementation of menuItems() function.

void menuItems()

{

// Display the Menu

cout << "=============================\n";

cout << " 1) Add an item to memory\n"

<< " 2) Search memory for an item \n"

<< " 3) List what's in memory\n"

<< " 4) Total value on hand\n"

<< " 5) Save to a file\n"

<< " 6) Read from a file\n"

<< " 0) Exit Program" << endl;

}

//main method.

int main()

{

//variable declaration.

int mnuChoice, cn = 0, d;

string n;

double sum = 0, c;

int temp;

string a, b;

string inputBuffer;

inventoryItem items[100];

ifstream inventoryFile("inventory.txt");

if (inventoryFile)

{

//store the data from the file to memory.

while (!(inventoryFile.eof()))

{

inventoryFile >> items[cn].itemName;

inventoryFile >> items[cn].itemNumber;

inventoryFile >> inputBuffer;

items[cn].itemPrice = atof(inputBuffer.c_str());

inventoryFile >> inputBuffer;

items[cn].itemQuantity = atoi(inputBuffer.c_str());

cn++;

}

inventoryFile.close();

ifstream inventoryFile("inventory.txt");

ofstream fout;

fout.open("inventory.txt");

do

{

menuItems();

cout << cn << " items stored." << endl;

// Prompt and read choice form the user

cout << "Enter your choice: ";

cin >> mnuChoice;

switch (mnuChoice)

{

//Add a new inventory item to the data in memory.

case 1:

// Prompt and read name of the item from the user

cout << "Enter name of the item: ";

cin >> inputBuffer;

items[cn].itemName = inputBuffer;

// Prompt and read itemNumber from the user

cout << "Enter the itemNumber: ";

cin >> inputBuffer;

items[cn].itemNumber = inputBuffer;

// Prompt and read itemPrice from the user

cout << "Enter the itemPrice: ";

cin >> inputBuffer;

items[cn].itemPrice = atof(inputBuffer.c_str());

// Prompt and read itemQuantity from the user

cout << "Enter the itemQuantity: ";

cin >> inputBuffer;

items[cn].itemQuantity = atoi(inputBuffer.c_str());

cn++;

break;

//Search the inventory for an item by inventory number.

case 2:

temp = 0;

cout << "Enter inventory itemNumber: ";

cin >> n;

for (int i = 0; i < cn&&temp != 1; i++)

{

// If found, print the stored info

if (items[i].itemNumber.compare(n) == 0)

{

// Display the stored information

cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;

cout << items[i].itemName << "\t " << items[i].itemNumber << " \t" << items[i].itemPrice << "\t " << items[i].itemQuantity << endl;

temp = 1;

}

// otherwise print 'not found'.

if (temp == 0)

{

cout << "Not found!!!" << endl;

}

break;

//List the inventory on the screen

case 3:

cout << "The data in the memory is:" << endl;

cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;

for (int i = 0; i < cn; i++)

{

cout << items[i].itemName << "\t " << items[i].itemNumber << "\t " << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;

}

break;

// Calculate the total value on hand.

case 4:

for (int i = 0; i < cn; i++)

{

// The sum is the accumulation of all the (quantities * prices).

sum += items[i].itemPrice*items[i].itemQuantity;

}

cout << "sum value on hand: " << sum << endl;

break;

// Save the inventory data in the given file

case 5:

for (int i = 0; i < cn; i++)

{

if (i == cn - 1)

{

fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity;

}

else

{

fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;

}

break;

// Read the data from the file

case 6:

while (!(inventoryFile.eof()))

{

inventoryFile >> a;

inventoryFile >> b;

inventoryFile >> inputBuffer;

c = atof(inputBuffer.c_str());

inventoryFile >> inputBuffer;

d = atoi(inputBuffer.c_str());

// Dsiplays the data in the file

cout << a << " " <

}

break;

}

// Check the menu choice is not equal to 0,

//if it is equal exit from the loop

} while (mnuChoice != 0);

// File closed

fout.close();

inventoryFile.close();

}

// If the inventory file does not exist

// and then display the error message.

else

{

cout << "File does not exist!" << endl;

}

return 0;

}

See more about C++ code at brainly.com/question/17544466

#SPJ1

5 0

2 years ago

Write a Python function that takes as input parameters base_cost (a float) and customer_type and prints a message with informati

PSYCHO15rus [73]

Answer:

Explanation:

Thanks for the question, here is the code in python

The 3rd example given in question is incorrect

inputs: check_amount = 26.99, customer_type = "generous" --> output: Total owed by stingy customer = $16.83 (with $1.53 tip)

the customer type in the above passed is generous but why the output is showing for stingy, I think this is incorrect

Here is the function, I have given explanatory names so that you can follow the code precisely and also used pretty formatting.

thank you !

===================================================================

def print_tip(base_cost, customer_type):

TAX_PERCENTAGE = 1.07

STINGY_PERCENTAGE = 0.1

REGULAR_PERCENTAGE = 0.15

GENEROUS_PERCENTAGE = 0.20

check_amount = base_cost * TAX_PERCENTAGE

tip_amount = 0.0

if customer_type == 'regular':

tip_amount = check_amount * REGULAR_PERCENTAGE

elif customer_type == 'generous':

tip_amount = check_amount * GENEROUS_PERCENTAGE

elif customer_type == 'stingy':

tip_amount = base_cost * STINGY_PERCENTAGE

total_amount = tip_amount + check_amount

print('Total owed by {} customer = ${} (with ${} tip)'.format(customer_type, '%.2f' % total_amount,'%.2f' % tip_amount))

print_tip(20, 'regular')

print_tip(26.99, 'generous')

print_tip(14.99, 'stingy')

8 0

3 years ago

What are the advantage of an e-library​

What are the advantage of an e-library