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3 years ago

How do u solve 4(-1/10)

Mathematics

1 answer:

Ede4ka [16]3 years ago

8 0

Answer:

The answer is -0.4

Step-by-step explanation:

First do the parentheses then multiple the answer with the number outside the parentheses.

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If r is ten more than the square root of l , then r = A) l2 + 10 B) (l + 10)2 C) l + 10 D) l + 10 E) l + 10

stiv31 [10]

Answer:

$r=\sqrt {I}+10$

Step-by-step explanation:

We first need to know the square root of I then add 10 on that square root since r is 10 more than the square root of I

Therefore,

$r=\sqrt {I}+10$

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3 years ago

Write the point-slope form of the equation of the line with a slope of - 2 and an x-intercept of - 1. Include your work in your

coldgirl [10]

X-intercept is -1 implies line passes through (-1,0).
So point slope form is

y - 0 = -2 (x -(-1) )

>> y = -2 (x +1) <----- FINAL ANSWER

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3 years ago

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Which order pair is a solution to the system of linear equations -4+y=8 and x-5y=17?

andreev551 [17]

Hello!

To find this ordered pair, we solve for x and y and put them together in an ordered pair.

-4+y=8

x-5y=17

Let's solve the first equation for y.

y= 12

Now, let's plug 12 into the second equation for y.

x-5(12)=17

x-60=17

x=77

Therefore, our ordered pair is (77,12)

I hope this helps!

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fenix001 [56]

Answer:

Step-by-step explanation:

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3 years ago

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What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$