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2 years ago

Set up equation for the following angles

Mathematics

2 answers:

maw [93]2 years ago

4 0

Add each angle for the question and make them equal 180

Example: number 15
(23x-5)+(21x+5)=180

valentinak56 [21]2 years ago

3 0

I think it's 23x-5=21x+5

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The office manager ordered145 packs of printer paper. Based on average daily use, she knows that the paper will last 65 days. Wh

erik [133]

The first or third graph represents the situation
After 25 days he would expect to have , i would say 88 packs left
I cant make out the bottom figure below third graph

5 0

2 years ago

The amount of money Tom has is 75% of Sallys amount of money. After Sally spent $120 and Tom saved all his money Tom's amount of

egoroff_w [7]

Answer: sally initially has $240, Tom initially has $180.

Step-by-step explanation:

Let initial amount of money sally has = x

Then, initial amount tom has = 75% * x = 0.75x

Now to present,

Amount sally has = x -120

Amount tom has = [x - 120] + [50% * (x-120)]

= x - 120 + 0.5x - 180

= 1.5x - 180

Since Tom didn't spend, it means this is the same amount tom has then we equate both equations.

0.75x = 1.5x - 180

180 = 0.75x

x = 240

Therefore, initial money of sally of sally = $240

Initial money of tom = 240 * 0.75 = $180.

6 0

2 years ago

Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a

Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = $\frac{1}{6}$

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

$E(X)=\sum x\cdot P(X=x)$

Compute the expected monetary value of a single roll as follows:

$E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17$

Thus, the expected monetary value of a single roll is $1.17.

7 0

3 years ago

The following is the correct way to show the product for 0.297×7.1:

ZanzabumX [31]

The answer is 2.1087

3 0

3 years ago

F(p)=4p+6

ycow [4]

Answer:sfj

Step-by-step explanation:

Vfgjn

8 0

2 years ago