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3 years ago

Is a box of feathers heavier than one single brick

Mathematics

2 answers:

klio [65]3 years ago

7 0

Bricks will be heavier than a box of feathers

Hope This Helps

slavikrds [6]3 years ago

4 0

No because feathers are light and bricks are heavey

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Please help easy stuff.......

nataly862011 [7]

To evaluate a function at a given input, you have to substitute every occurrence of the variable with that particular value.

So, for the first function, you have

$T(x) = -x-2 \implies T(-4) = -(-4)-2 = 4-2 = 2$

The name of the variable is obviously irrelelvant, so the same goes for the second function:

$w(x) = 14-6x \implies w(-3) = 14-6\cdot(-3) = 14 + 18 = 32$

3 0

2 years ago

Read 2 more answers

Can someone help me with this one

Viktor [21]

Answer:

y = -4x + (-2)

Step-by-step explanation:

if you plug in the x values in the equation it equals y

4 0

3 years ago

G verify that the divergence theorem is true for the vector field f on the region

Alenkasestr [34]

$\mathbf f(x,y,z)=\langle z,y,x\rangle\implies\nabla\cdot\mathbf f=\dfrac{\partial z}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial x}{\partial z}=0+1+0=1$

Converting to spherical coordinates, we have

$\displaystyle\iiint_E\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=6}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=288\pi$

On the other hand, we can parameterize the boundary of $E$ by

$\mathbf s(u,v)=\langle6\cos u\sin v,6\sin u\sin v,6\cos v\rangle$

with $0\le u\le2\pi$ and $0\le v\le\pi$ . Now, consider the surface element

$\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\dfrac{\mathbf s_v\times\mathbf s_u}{\|\mathbf s_v\times\mathbf s_u\|}\|\mathbf s_v\times\mathbf s_u\|\,\mathrm du\,\mathrm dv$
$\mathrm d\mathbf S=\mathbf s_v\times\mathbf s_u\,\mathrm du\,\mathrm dv$
$\mathrm d\mathbf S=36\langle\cos u\sin^2v,\sin u\sin^2v,\sin v\cos v\rangle\,\mathrm du\,\mathrm dv$

So we have the surface integral - which the divergence theorem says the above triple integral is equal to -

$\displaystyle\iint_{\partial E}\mathbf f\cdot\mathrm d\mathbf S=36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv$
$=\displaystyle36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}(12\cos u\cos v\sin^2v+6\sin^2u\sin^3v)\,\mathrm du\,\mathrm dv=288\pi$

as required.

3 0

3 years ago

( x + 3 ) + ( − 7 x − 1 )

lora16 [44]

Answer:

-6x +2

Step-by-step explanation:

( x + 3 ) + ( − 7 x − 1 )

Combine like terms

x -7x +3 -1

-6x +2

8 0

2 years ago

Read 2 more answers

1. Rahul started his homework at 5.25 and ended his homework at 6:40. Find the elapsed time.

Darya [45]

Answer:

1. 75 minutes

2. 5:50

Step-by-step explanation:

you have to add and subtract

8 0

3 years ago