See the attached figure to better understand the problem
we know that
AM=MD
so
triangle AMD is an isosceles right triangle
therefore
its height is half its width.
Then
AB = (1/2)AD----------Equation 1
Perimeter=2*[AB+AD]=34 in ---------> AB+AD=17-------> Equation 2
I substitute 1 in 2
(1/2)AD +AD = 17
(3/2)AD=17
AD=17*2/3----------> AD=34/3-------> 11 1/3 in
AB=(1/2)AD--------> AB=(1/2)*34/3--------> AB=17/3-------> AB=5 2/3 in
the answers are
AD=11 1/3 inAB = 5 2/3 in
Step-by-step explanation:
Let the length be L.
Let the breath be B.
So, we are given that
length of a rectangle is 7 inches greater than three times its width .
So, according to the Question,
L = 7+ 3B.
So, we know that:-
Area = Length× Breadth.
So, it will be
B × (7 + 3B) = Area.
So,
3B² + 7 is an expression to represent its area.
Answer:
You prove the base angles are congruent by constructing the angle bisector through the vertex angle of an isosceles triangle. By constructing the angle bisector, we designed two congruent triangles and then used CPCTC to show that the base angles are congruent.
Step-by-step explanation: