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MAVERICK [17]
3 years ago
10

How to write 23 minutes after 4

Mathematics
2 answers:
Sonbull [250]3 years ago
8 0
4:23 Is 23 minutes after 4! :)
olga_2 [115]3 years ago
6 0
To write 4 as a time you write 4:00,  Then the word after means to add 23 minutes to the 4 so we have 4:23
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There are 15 technicians and 11 chemists working in a research lab. They need to form a 5 person safety committee. In how many w
Burka [1]
<h2>There are a total 65,780 ways in which the committee can be made of 5 members.</h2>

Step-by-step explanation:

Here, the total number of technicians in the lab = 15

The total number of chemists in the lab  = 11

So, the total members in the lab  = 15 + 11 = 26

So, there are total 26 eligible candidates in the lab from which committee of 5 people has to be made.

Now, since there is <u>no restrictions</u> on the choice, so the committee can be formed in nay way, such that:

It may or may not have any technician.

It may or may not have may chemists.

So, the number of ways 5 member can randomly be chosen from a committee of 26 people  = ^{26} C_5

^{26} C_5 = ^{26} C_5 = \frac{26!}{5! \times 21!}  = 65,780

Hence, there are a total 65,780 ways in which the committee can be made of 5 members.

5 0
3 years ago
1. Rewrite the equation 5(x - 3) = x + 13 with 6 substituted for x. Write a
soldier1979 [14.2K]

Answer:

Step-by-step explanation:

5(6-3)=6+13 -simplify

30-15=6+13

15=19

x doesnt equal 6

5(x-3)=x+13

5x-15=x+13

4x=28

x=7

4x=28

4(7)=28

28=28

4 0
3 years ago
2
Irina18 [472]

Answer:

Value of X is –5

Step by step explanation:-

2x – 3 + 3x = – 28

=> 5x = –28 + 3

=> 5x = –25

=> x = –25/5

=> x = –5

6 0
3 years ago
Pierre is rowing his kayak on a lake. He moves miles in 18 minutes. At this rate, how far would he move in 30 minutes?
Anika [276]

Answer:

Step-by-step explanation:

times the number so 18 times 30

5 0
4 years ago
Read 2 more answers
Which pair of equations represents perpendicular lines?
OLEGan [10]
The\ slope-intercept\ form:y=mx+b\\\\k:y=m_1x+b_1\ and\ l:y=m_2x+b_2\\\\k\perp l\iff m_1\cdot m_2=-1\Rightarrow m_2=-\frac{1}{m_1}\\-----------------------\\therefore\\a)\ m_1=\frac{1}{2};\ m_2=-\frac{1}{2}\ \boxed{NOT\ :(}\\\\b)\ m_1=5;\ m_2=-\frac{1}{5}\ \boxed{YES\ :)}\ \ 5\cdot(-\frac{1}{5})=-1\\\\c)\ m_1=\frac{1}{5};\ m_2=\frac{1}{5}\ \boxed{NOT\ :(}\\\\d)\ m_1=3;\ m_2=6\ \boxed{NOT\ :(}
3 0
3 years ago
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