Let's look at the terms of the sequence for different values of n, starting from 0.
a₀ = 0/1 = 0
a₁ = 1/(1 +1) = 1/2
a₂ = 2/(2 + 1) = 2/3
a₃ = 3/(3 + 1) = 3/4
a₄ = 4/5
a₅ = 5/6
a₆ = 6/7
a₇ = 7/8
a₈ = 8/9
a₉ = 9/(9+1) = 9/10
a₁₀ = 10/(10+1) = 10/11 and so on
Let's look at the terms. As n gets bigger the terms gets closer to 1. We started with 0, then to one half, then two thirds, and as we get larger and larger, the terms are getting closer to 1. Let's choose a really big n and see.
a₉₉₉ = 999/(999 + 1) = 999/1000
Or an even bigger n:
a₉₉₉₉₉₉₉₉₉ = 999999999/(999999999 + 1) = 999999999/1000000000ⁿ
So as n gets really really large - and close to infinity - the terms get closer to 1.
Answer:
A
Step-by-step explanation:
For this case what you should see is each of the edges of the prism that are parallel.
We then have as parallel edges:
AC and GE
CG and AE
CD and GH
AB and EF
BD and HF
DH and BF
CD and EF
GH and AB
Answer:
8 pairs of parallel lines
We have been given that a culture of bacteria has an initial population of 22,000 bacteria and doubles every 5 hours. Using the formula 
, where P(t) is the population after t hours, 
is the initial population, t is the time in hours and d is the doubling time.
We are asked to find the population of bacteria after 17 hours.
First of all, we will substitute our given values in doubling life formula as:
Now to find population of bacteria after 17 hours, we will substitute 
in our formula as:
Therefore, the bacteria population will be 232,233 after 17 hours.
The two consecutive integers are 2 and 3
<em><u>Solution:</u></em>
Let x and x + 1 are the two consecutive integers
Let "x" be the smallest integer
Let "x + 1" be the larger integer
<em><u>Given that, sum of 2 consecutive integers is one less than 3 times the smaller integer</u></em>
Therefore,
sum of 2 consecutive integers = one less than 3 times the smaller integer
sum of 2 consecutive integers = 3 times the smaller integer - 1
x + x + 1 = 3(x) - 1
2x + 1 = 3x - 1
3x - 2x = 1 + 1
x = 2
Thus the smaller integer = x = 2
Larger integer = x + 1 = 2 + 1 = 3
Thus the two consecutive integers are 2 and 3
