10080 is the number nearest to 10000 that is divisible by 3, 4, 5, 6, 7, and 8.
Divisibility is being able to divide a number evenly and result to a whole number. Divisibility rules are set of rules to test if one number is divisible by another without doing much computation.
#1: divisibility by 2
A number is divisible by 2 if its last digit is even.
# 2: divisibility by 3:
A number is divisible by 3 if the sum of its digits is divisible by 3.
# 3: divisibility by 4
A number is divisible by 4 if the number represented by its last two digits is divisible by 4.
#4: divisibility by 5
A number is divisible by 5 if its last digit is 0 or 5.
# 5: divisibility by 6
A number is divisible by 6 if it is divisible by both 2 and 3.
# 6: divisibility by 7
Double the last digit and subtract it from a number made by the other digits. The result must be divisible by 7.
#7: divisibility by 8
A number is divisible by 8 if the number represented by its last three digits is divisible by 8.
#8: divisibility by 9
A number is divisible by 9 if the sum of its digits is divisible by 9.
# 9: divisibility by 10
A number is divisible by 10 if its last digit or the digit in the ones place is 0.
To get the number nearest to 10000 that is divisible by 3, 4, 5, 6, 7, and 8, consider first the numbers that are divisible by 5(numbers ending in 5 or 0) and narrow it down to numbers ending in 0 since numbers ending in 5 is not divisible by 2, thus making it indivisible by 6.
The process goes on by narrowing the list by checking its divisibility by 3, 4, 7 and 8.
To know more about divisibility rules, visit brainly.com/question/9462805.
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to 4. Your problem should look like: 4 x 1. 
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