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Aloiza [94]
3 years ago
14

Help help ASAP ASAP

Mathematics
1 answer:
Sophie [7]3 years ago
4 0

Answer:

1

Step-by-step explanation:

y2 - y1 / x2 - x1

6 - 4 / 0 - -2

2 / 2 = 1

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Classify the following triangle. Check all that apply .
Artist 52 [7]

Answer:

Right and Isosceles

Step-by-step explanation:

The triangle is right because it has a 90-degree angle. It is also Isosceles because it has two side lengths that are equal.

7 0
3 years ago
Read 2 more answers
Somebody please help me ive been trying for hours
elixir [45]

Answer:

width = 5k^2

length( 3k^2 +7k +4)

Step-by-step explanation:

15k^4 +35k^3 +20k^2

The width is the greatest common factor

We can factor 5k^2 out

5k^2( 3k^2 +7k +4)

The length is what is inside the parentheses

4 0
4 years ago
How many collections of six positive, odd integers have a sum of 18? Note that 1 + 1 + 1 + 3 + 3 + 9 and 9 + 1 + 3 + 1 + 3 + 1 a
san4es73 [151]

Answer:

  11

Step-by-step explanation:

Suitable software can generate these collections. They are ...

{13,1,1,1,1,1}, {11,3,1,1,1,1}, {9,5,1,1,1,1}, {9,3,3,1,1,1},

{7,7,1,1,1,1}, {7,5,3,1,1,1}, {7,3,3,3,1,1}, {5,5,5,1,1,1},

{5,5,3,3,1,1}, {5,3,3,3,3,1}, {3,3,3,3,3,3}}

5 0
3 years ago
M in
klio [65]

Answer:

The copy machine makes 87.5 copies in one minute.

Step-by-step explanation:

Set up an equation to divide 4 into 350. This is because in order to know how many copies is being made in 1 minute, you need to determine the rate of copies per minute.

350 divided by 4 is 87.5.

3 0
3 years ago
Express the following relations in the set builder notation. Then, determine whether it is reflexive, symmetric, transitive. Ple
pshichka [43]

Answer:

a)Reflexive, not symmetric, transitive

b)Reflexive, not symmetric, transitive

c)Not reflexive, symmetric, not transitive

d)Reflexive, not symmetric, transitive

Step-by-step explanation:

a)

R=\left \{ (a,b)\epsilon  \mathbb{R} \times \mathbb{R} \mid a \leq b\right \}

The relation R is reflexive for

a\leq a for every real number a

it is not symmetric because 0 is less than 1, but 1 is not less than 0

it is transitive

a\leq and b\leq c\Rightarrow a\leq c

So if aRb and bRc, then aRc

b)  

R=\left \{ (m,n)\epsilon  \mathbb{Z} \times \mathbb{Z} \mid \exists k\in \mathbb{Z} \ni m=kn \right \}

R is reflexive because m=1.m for every integer m

R is not symmetric: 2 is a factor of 4, but 4 is not a factor of 2

R is transitive:  if mRn and nRp if m=kn and n=qp, so m=(kq)p and kq is an integer , so mRp

c)

R=\left \{ (m,n)\epsilon  \mathbb{Z} \times \mathbb{Z} \mid m\neq n\right \}

R is obviously not reflexive because all numbers equals themselves

R is symmetric: if a different to b, then b different to a

R is not transitive: 1R2 and 2R1 (because 1 different to 2), but 1 = 1

d)

R=\left \{ A,B\mid A\subseteq B \right \}

R is reflexive for every set A is a subset of itself

R is not symmetric {1,2} is a subset of {1,2,3} but {1,2,3} is not a subset of {1,2}

R is transitive: if A is subset of B and B is subset of C, then A is subset of C

8 0
4 years ago
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