I believe the answer is B.
Hi there
x² + 7x = -10
x² + 7x + 10 = 0
Now, we can factor left side
(x+2)(x+5) = 0
Set factors equal to 0
x + 2 = 0 or x + 5 = 0
x = 0 - 2 or x = 0 - 5
x = -2 or x =-5
I hope that's help !
Answer: your gonna add 3,000+ 5,000 then you will add test answer to 157.50 then you’ll put the answer for 3,000+5,000 then you’ll put that in the first box then you’ll add that number two 157.50
Step-by-step explanation:
Hope this helps
:3 have an amazing day or a beautiful day:)
Answer:
The maximum number of red beans that can be put in one of the stacks is 5.
Step-by-step explanation:
First, Every pile is made with 7 beans, but they need to have at least one bean of each color, so we need to include in the pile minimum one yellow bean and one green bean. If we make a stack with this condition, the stack is going to have: 1 yellow bean, 1 green bean, and 5 red beans.
Additionally, it is necessary to know if there are enough red beans for the other piles. In this case, we have 10 red beans so if we have 5 red beans in one stack, the other two stacks have enough red beans to fulfill with the condition to have at least one red bean.
So, the maximum number of red beans that can be put in one of the stacks is 5.
