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2 years ago

5

Which of the following is equivalent to f(x)=27^5/3x

1 answer:

sergey [27]2 years ago

6 0

The process and answer are in the picture. If you’re satisfied, could you please give me a brilliant answer! :)

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PLEASE HELP :DDDDDDDDDD

Maslowich

Ok start off by finding the base first and the equation of finding the area of the square is A=bh
A=11 x 11= 121 cm^2

Next find the area of one triangle and the equation is A=1/2bh
A=1/2(11)(10)
A=55 cm^2

Multiply the area of one triangle by 4 since there are four triangles and it should equal to 220 cm^2. You then add this to the base and the final answer should be 341 cm^2.

I hope this helps

6 0

3 years ago

Read 2 more answers

A large tank is filled to capacity with 300 gallons of pure water. Brine containing 5 pounds of salt per gallon is pumped into t

Gwar [14]

Answer:

(a) $A = 1500(1 - e^{-0.01t})$

(b) $t = 0$

Step-by-step explanation:

Given

$V= 300gal$ --- Volume of tank

$B = 5lb/gal$ --- Brine solution

$R_1 = 3gal/min$ --- Rate in, in gallon/min

$R_2 = 6gal/min$ --- Rate out, in gallon/min

Required

Determine A(t)

First, calculate the rate in (R in) and (R out) in lb/min

$R_{in} = B * R_1$

$R_{in} = 5lb/gal * 3gal/min$

$R_{in} = 15lb/min$

R(out) is calculated by multiply the rate at which brine leaves the tank (lb/gal) * R2

So, we have:

$R_{out} = \frac{A(t)}{300} lb/gal * 3gal/min$

$R_{out} = \frac{3*A(t)}{300} lb/min$

$R_{out} = \frac{A(t)}{100} lb/min$

The change in the amount of brin e in the tank at time t is given as:

$A'(t) = R_{in} - R_{out}$

$A'(t) = 15 - \frac{A(t)}{100}$

Rewrite:

$\frac{dA}{dt} = 15 - \frac{A}{100}$

Multiply through by dt

$dA = [15 - \frac{A}{100}]* dt$

Make dt stand alone

$\frac{dA}{15 - \frac{A}{100}} = dt$

$ln|15 - \frac{A}{100}| = -0.01t + ln\ c$

Express as exponents

$15 - \frac{A}{100} = ce^{-\frac{t}{100}}$

Multiply through by 100

$1500 - A = 100ce^{-\frac{t}{100}}$

$A = 1500 - 100ce^{-\frac{t}{100}}$

$A = 1500 - 100ce^{-0.01t}$

Apply initial conditions

$A(0) = 0$

Substitute 0 for t in: $A = 1500 - 100ce^{-0.01t}$

$0 = 1500 - 100ce^{-0.01*0}$

$0 = 1500 - 100ce^{0}$

$0 = 1500 - 100c$

$100c = 1500$

$c = 15$

Substitute 15 for c in $A = 1500 - 100ce^{-0.01t}$

$A = 1500 - 100*15e^{-0.01t}$

$A = 1500 - 1500e^{-0.01t}$

Factorize:

$A = 1500(1 - e^{-0.01t})$

How long to empty the tank

Set A to 0

$1500(1 - e^{-0.01t}) = 0$

Divide through by 1500

$1 - e^{-0.01t} = 0$

Collect Like Terms

$e^{-0.01t} = 1$

Take ln of both sides

$ln\ (e^{-0.01t}) = ln\ 1$

$-0.0t = 0$

$t = 0$

8 0

3 years ago

25 POINTS + BRAINLIEST

Yanka [14]

Answer:

It should be A) 54

Step-by-step explanation:

32 + 14 + 8 = 54

3 0

3 years ago

Round 458,673 to the nearest hundred thousand

Viefleur [7K]

500,000 is that number rounded.

4 0

3 years ago

Read 2 more answers

(Please show your work) (1 kwh = 3400 BTU’s 1 gallon = 8 pounds of water) The water coming into a dishwasher from a water heater

shtirl [24]

Answer:

5700 BTU

Step-by-step explanation:

Data provided in the question:

1 kwh = 3400 BTU’s

1 gallon = 8 pounds of water

Initial temperature = 50°F

Final temperature = 100°F

Water used by dishwasher = 10 gallons

Electrical energy used = 0.5 kwh

Now,

Water used in pounds = 10 × 8 = 80 lb

Total electrical energy used in BTU = 0.5 × 3400 BTU [ as 1 kwh = 3400 BTU]

Total electrical energy used in BTU = 1700 BTU

Energy used by water = Water used by dishwasher × Change in temperature × Specific heat of water

[ Specific heat of water = 1 BTU / °F.lb ]

Thus,

Energy used by water = 80 × 1 × ( 100 - 50 )

= 4000 BTU

Hence,

Total energy used = 1700 BTU + 4000 BTU = 5700 BTU

8 0

3 years ago