10/13 = 1% = 0.769230769
1%*100 = 100% 0.769230769*100 = 76.9230769 = 76.92
If you look in the back off your book if that’s a odd question you can see the answers
1152 grams of iron are required to make the alloy when combined with 144 grams of zinc
Step-by-step explanation:
We will use the proprtion to solve the problem
Let x2 be the quantity of iron when combined with 144 grams of zinc
So,
zinc in first alloy = z1 = 9 gm
Iron in first alloy = x1 = 72 gm
Zinc in second alloy = 144 gm
So,

Hence,
1152 grams of iron are required to make the alloy when combined with 144 grams of zinc
Keywords: Fractions, proportion
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