double bracket factorisation
2 × 15 = 30
find two factors of 30 that add to give -7
(-10, +3)
2x^2 -10x + 3x - 15
2x(x-5) + 3 (x-5)
<em><u>(</u></em><em><u>2x</u></em><em><u>+</u></em><em><u>3</u></em><em><u>)</u></em><em><u> </u></em><em><u>(</u></em><em><u>x-5</u></em><em><u>)</u></em>
<em><u>THE</u></em><em><u> </u></em><em><u>ANSWER</u></em><em><u> </u></em><em><u>IS</u></em><em><u> </u></em><em><u>X-5</u></em>
Just multiply directly numerator with numerator and denominator with denominator
Well I would say multiply 16*4 to get 64 so unless you want to answer it, the answer is (-5*64) is your simplified equation. ()- is just to separate from the words
* - is multiply symbol. This is much more useful when using variables so your X variable don't get mixed up.
C but i could be wrong lol very wrong.
Answer: The correct option is
(D) 60.
Step-by-step explanation: Given that the number of stamps that Kaye and Alberto had were in the ration of 5:3 respectively.
After Kaye gave Alberto 10 of her stamps, the ration of the number of Kaye had to the number of Alberto had was 7:5.
We are to find the number of stamps that Kaye had more than Alberto.
Let the number of stamps Kaye and Alberto has are 5x and 3x respectively.
Then, according to the given information, we have

So, the number of stamps that Kaye had = 5 × 30 = 150
and
the number of stamps that Alberto had = 3 × 30 = 90.
Therefore, the number of stamps that Kaye had more than Alberto is

Thus, Kaye had 60 stamps more than Alberto.
Option (D) is CORRECT.