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2 years ago

Formula of perimeter and area

Mathematics

2 answers:

Llana [10]2 years ago

6 0

Answer:

Hey Friend....

Step-by-step explanation:

This is ur answer....

<h3>Perimeter</h3>

<em>Square = 4a</em>

<em>Rectangle = 2 (I + b) </em>

<em>Square = a x a</em>

<em>Rectangle = I x</em><em> </em><em>b</em>

Hope it helps!

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OverLord2011 [107]2 years ago

5 0

Answer:

Perimeter: 4 * s

Area: S 2

Diagonal: s 2 \sqrt {2} 2

Area of square when diagonal is given = 1 2 × d 2 \frac {1} {2}\times d^ {2} 21 × d2

Step-by-step explanation:

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Help me please edddd

nydimaria [60]

Answer:

the second one 9v+36

Step-by-step explanation:

because with the way it set up it wants you to multiply 9 by everything inside of the parenthesis so 9 times v is 9v and 9 times 4 is 36 thus 9v+36 and you also take the addition symbol from inside the parenthesis.

3 0

2 years ago

Read 2 more answers

PROBLEM: Riley has a rectangular shaped patio that is 13 feet long by 15 feet wide. He wants to DOUBLE THE AREA of the patio by

photoshop1234 [79]

Answer:

1) The equation that represents the total area of Riley's proposed ratio is $A' = (\sqrt{2}\cdot x)\cdot (\sqrt{2}\cdot y)$ .

2) The length and width of the new patio are approximately 18.4 feet and 21.2 feet, respectively.

Step-by-step explanation:

1) From Geometry we remember that area formula for the rectangle is represented by:

$A = x\cdot y$ (1)

Where:

$A$ - Area, measured in square feet.

$x$ - Length, measured in feet.

$y$ - Width, measured in feet.

From statement we know that Riley wants to double the area, that is:

$A' = 2\cdot A$ (2)

By applying (1) in (2), we get the following expression:

$A' = 2\cdot x\cdot y$ (3)

Given that Riley wants to double the area of the pation by increasing the length and width by the same amount, we can rearrange (3) by algebraic means:

$A' = \sqrt{2}\cdot \sqrt{2}\cdot x\cdot y$

$A' = (\sqrt{2}\cdot x)\cdot (\sqrt{2}\cdot y)$ (3b)

The equation that represents the total area of Riley's proposed ratio is $A' = (\sqrt{2}\cdot x)\cdot (\sqrt{2}\cdot y)$ .

2) If we know that $x = 13\,ft$ and $y = 15\,ft$ , then the length and the width of the new patio are, respectively:

$x' = \sqrt{2}\cdot x$

$x' = \sqrt{2}\cdot (13\,ft)$

$x' \approx 18.4\,ft$

$y' = \sqrt{2}\cdot y$

$y' = \sqrt{2}\cdot (15\,ft)$

$y' \approx 21.2\,ft$

The length and width of the new patio are approximately 18.4 feet and 21.2 feet, respectively.

8 0

2 years ago

I need help figuring out when to use law of sine or law of cosine?

irina [24]

When you have angle and its corresponding (opposite) side then you need to use law of sin. Problems 3,4,5(in 5 you need at first find angle X=180-92-62)

when you have two sides and angle between them, this is law of cos, problem 6,8

problem 7 you can use both, but if you can use both better to use law of sin, it is just easier

4 0

3 years ago

I need help with this what’s the answer

matrenka [14]

Answer:

If we look at the table we notice that 2 + 4 = 6, 3 + 4 = 7, 4 + 4 = 8 and so on so the equation is y = x + 4.

3 0

3 years ago

Read 2 more answers

Complete the like terms to create an equvalent expression:<br> -4r - 2r + 5

Marat540 [252]

-6r+5
the two like terms are the ones with R. combine -4r and -2r to get -6r

3 0

2 years ago

Formula of perimeter and area ​

Formula of perimeter and area