For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Answer:
Step-by-step explanation:
The rules For fractions: Multiple Denominator to Denominator and Numerator to numerator!
Ok: For number 1
3/5*1/1= 3/5
Number 2
3/4*9/4=27/16= 1 11/16
Number 3
14/21=2/3*33/7=66/21= 3 3/21= 3 1/7
Number 4
6/18*9/42= 1/3*3/14= 3/42= 1/14
Number 5
22/15*45/4= 33/2=16 1/2
Number 6
3/28* 35/6= 105/168= 5/8
Number 7
2/7*35/12=60/84=5/6
Number 8
16/15*21/24=16/15* 7/8=112/120=14/15
Hope It helps!!!!
Answer:
BC is equal to 7
Step-by-step explanation:
18 = 2x + 4
18 - 4 = 14
14 = 2x
14/2 = 7
7 = x
Answer:
y=3x+2
Step-by-step explanation:
- Perpendicular=P=4
- Base=B=4
Hypotenuse be H
Apply Pythagorean theorem
