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zaharov [31]
2 years ago
10

Please answer this ASAP

Mathematics
1 answer:
k0ka [10]2 years ago
5 0

Answer:

c: x=2

Step-by-step explanation:

5x-3= 13-3x

   +3      +3

5x=16-3x

+3      +3

8x=16

divide all of it by 8 and thats how you get your answer

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How many weeks will it take him to afford a car worth £1932
andreev551 [17]
7 hours a day
7 x €9.20 = €64.4 per day

6 days a week
€64.4 x 6 = €386.4 per week

Will:Mum = 5:2

386.4 / 7 = 55.2

Will: 55.2 x 5 = 276

After shares his wages, Will makes $276 a week

<span>1932 / 276 = 7 weeks</span>

<span>
</span>

<span>answer</span>

<span>7 weeks</span>

4 0
3 years ago
Which two ratios represent quantities that are proportional?
Ad libitum [116K]

Answer:

All 4 of them

Step-by-step explanation:

Tell me if I'm wrong

3 0
2 years ago
Andy has three planks of wood. Two planks are each 1.5 m long. One plank is 2.5m long. What is the total length of all the three
11Alexandr11 [23.1K]

Given:

Two planks are each 1.5 m long.

One plank is 2.5m long.

To find:

The total length of all the three planks.

Solution:

Two planks are each 1.5 m long. So,

First plank = 1.5 m

Second plank = 1.5 m

One plank is 2.5m long. So,

Third plank = 2.5 m

Now, the total length of all the three planks is

\text{Total length}=\text{First plank + Second plank + Third plank}

\text{Total length}=1.5+1.5+2.5

\text{Total length}=5.5

Therefore, the total length of all the three planks is 5.5 m.

4 0
3 years ago
he number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.02
Yakvenalex [24]

Answer:

a) 98.01%

b) 13.53\%

c) 27.06%

Step-by-step explanation:

Since a car has 10 square feet of plastic panel, the expected value (mean) for a car to have one flaw is 10*0.02 = 0.2  

If we call P(k) the probability that a car has k flaws then, as P follows a Poisson distribution with mean 0.2,

P(k)= \frac{0.2^ke^{-0.2}}{k!}

a)

In this case, we are looking for P(0)

P(0)= \frac{0.2^0e^{-0.2}}{0!}=e^{-0.2}=0.9801=98.01\%

So, the probability that a car has no flaws is 98.01%

b)

Ten cars have 100 square feet of plastic panel, so now the mean is 100*0.02 = 2 flaws every ten cars.

Now P(k) is the probability that 10 cars have k flaws and  

P(k)= \frac{2^ke^{-2}}{k!}

and  

P(0)= \frac{2^0e^{-2}}{0!}=0.1353=13.53\%

And the probability that 10 cars have no flaws is 13.53%

c)

Here, we are looking for P(1) with P defined as in b)

P(1)= \frac{2^1e^{-2}}{1!}=2e^{-2}=0.2706=27.06\%

Hence, the probability that at most one car has no flaws is 27.06%

6 0
3 years ago
Read 2 more answers
Write an expression that is equal to 3 times 2 and 1 /4
koban [17]
3x2x(1/4)= ????? And then u find the answer
6 0
2 years ago
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