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kobusy [5.1K]
3 years ago
8

Factorize 2x²-xy-y²-3x-6y-9 equals 0

Mathematics
1 answer:
amm18123 years ago
6 0

Answer:

(x - y - 3)(x + 1/2 y + 3/2) = 0

or  (x - y - 3)(2x + y + 3) = 0

Step-by-step explanation:

see attached for step-by-step

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Val returned a bicycle while she was on vacation. She paid a flat rental fee of $55.00 plus $8.50 each day. The total cost was $
andrew-mc [135]

Answer:

8 days

Step-by-step explanation:

The total cost includes $55 flat rental fee which is one time cost only as not given everyday so we subtract it from $123 and divide $(123-55) with per day cost that is $8.50 which gives 8 as answer so Val spent 8 days on vacation.

6 0
3 years ago
Please help? <br> I don’t understand this
Brut [27]

Answer:

Please see the graph below

Step-by-step explanation:

The table is just selecting numbers for x and then solving for what y would be.  Once we have the ordered pairs (x,y)  We can graph the points and see the line.

3 0
1 year ago
A chemistry teacher needs to mix a 20% salt solution with a 80% salt solution to make 25 qt of a 44% salt solution. How many qua
NNADVOKAT [17]
Let there be x quarts of the 20% salt solution, and (25 - x) quarts of the 80% salt solution.
Then the total amount of salt in the 20% portion would be 0.2x, while that from the 80% portion would be (0.8)(25 - x). This would have to total up to (0.44)(25) in the final solution, so the equation is:
0.2x + 0.8(25 - x) = (0.44)(25)
-0.6x + 20 = 11
x = 15 quarts of the 20% salt solution
25 - x = 10 quarts of the 80% salt solution
5 0
3 years ago
Whats the difference of 12-33/4
valentina_108 [34]
12 subtracted by 33 divided by 4 equals 3.75
8 0
3 years ago
Read 2 more answers
Basic Computation: Testing M1 2 M2 A random sample of 49 measurements from a population with population standard deviation 3 had
Elenna [48]

Answer:

The sample statistics follows a standard normal distribution since the sample size are large enough.

Step-by-step explanation:

Given that:

<u>First population:</u>

Sample size n_1 = 49

Population standard deviation \sigma_1  = 3

Sample mean \overline x _1= 10

<u>Second population:</u>

Sample size n_2 = 64

Population standard deviation \sigma_2= 4

Sample mean \overline x_2= 12

The sample statistics follows a standard normal distribution since the sample size are large enough.

The null and alternative hypotheses can be computed as:

\mathbf{H_o:\mu_1=\mu_2}

\mathbf{H_1:\mu_1\ne\mu_2}

Level of significance  = 0.01

Using the  Z-test statistics;

Z = \dfrac{\overline x_1 - \overline x_2}{\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}}

Z = \dfrac{10- 12}{\sqrt{\dfrac{3^2}{49} + \dfrac{4^2}{64}}}

Z = \dfrac{-2}{\sqrt{\dfrac{9}{49} + \dfrac{16}{64}}}

Z = \dfrac{-2}{\sqrt{0.18367 +0.25}}

Z = \dfrac{-2}{\sqrt{0.43367}}

Z = \dfrac{-2}{0.658536}

Z = - 3.037

Z \simeq - 3.04

The P-value = 2P (z < -3.04)

From the z tables

= 2 × (0.00118)

= 0.00236

Thus, since P-value is less than the level of significance, we fail to reject the null hypotheses H_o

5 0
3 years ago
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