Answer:
The intensity of the 2011 earthquake was about 6 times the intensity of the 2003 earthquake.
Step-by-step explanation:
To compare the intensities, we first need to convert the magnitudes to intensities using the log formula. Then we will set up a ratio to compare the intensities.
Convert the magnitudes to intensities and write them in exponential form.
R=logI
2011 earthquake:
9.1I=logI=109.1
2003 earthquake:
8.3I=logI=108.3
Form a ratio of the intensities.
intensity for 2011intensity for 2003
Substitute in the values and divide by subtracting the exponents to find
109.1108.3100.8≈6.
The intensity of the 2011 earthquake was about 6 times the intensity of the 2003 earthquake.
Your answer:
The intensity of the 2011 earthquake was about 15 times the intensity of the 2003 earthquake.
Area is a^2
the side length is 100 ft
100^2 = 10,000
Answer:
y = 3x - 5
Step-by-step explanation:
I used my calculator so that it would be faster.
But if you want work you have to find the slope then plug in.
To find the slope use points (1, -2) and (2, 1) use this formula
Plug the points in
So your slope is 3
NOw Plug In (1, -2)
-2 = 3(1) + b (b represents the y- intercept)
-2 = 3 + b (subtract 3 on both sides)
-5 = b
The final equation is y = 3x - 5
Hope this helps ya!!
Answer:
x = 11/2 = 5.5
Step-by-step explanation:
2x-6 = 5
2x = 11
x = 11/2 = 5.5
First we need to determine the type of progression in the question.That's geometric progression. Because the pattern from one sequence to the others are about multiplying.
Second, determine the ratio of the progressionr = a₂/a₁
r = a₂ ÷ a₁
r = 1/2 ÷ 2
r = 1/2 × 1/2
r = 1/4
Third, determine the formula to know the recursive rulea₂ = a × 1/4
a₂ = 1/4 × a
Fourth, determine a₁. a₁ is the first term of the progressiona₁ = 2
Final answer:Recursive rule
a₁ = 2