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3 years ago

Hi please help :)))))))

Mathematics

2 answers:

antoniya [11.8K]3 years ago

5 0

Answer
There’s No difference
Explanation

lesya [120]3 years ago

3 0

Answer:

there is no difference

Step-by-step explanation:

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timmy was asked to order nine pizzas, with the following orders: one pepperoni and one cheese how many did he order in total

Romashka [77]

11 pizza's.

9 + 1 + 1 = 11

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3 years ago

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Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The cumulative distribution for this function is given by:

$F(X) = 1- e^{-\lambda x}, x\ geq 0$

We know the value for the mean on this case we have that :

$mean = \frac{1}{\lambda}$

$\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367$

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: $Var(X) =\frac{1}{\lambda^2}$

And the deviation would be:

$Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725$

And the mean is given by $Mean = 2.725$

Two deviations correspond to 5.540, so we want this probability:

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

$P(X$

8 0

3 years ago

Can someone please tell me the answer

Vilka [71]

Answer:

36 since they are similer triangles

Longer process:

24/24 = 36/x

solve this and you get 36

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2 years ago

5, 10, 12, 4, 6, 11, 13, 5<br> calculate the median <br> show your work

Zinaida [17]

First you want to organize it from least to greatest: 4, 5, 5, <em>6, 10</em>, 11, 12, 13

Then look for the one in the middle. But oh wait there are 2 so you need to add 6 and 10 then divide it by 2 to get a median of 8.

A song I learned back then is this I don't know who it is by though: Mode, mode, mode is the most, Average is the mean.Median, median, median, median, The number in between.

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3 years ago

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MIKE NEEDS AT LEAST $100 TO BUY A NEW SUIT FOR THE DANCE.

Tanya [424]

Answer:

3x+10 = 100

100 - 10 = 3x

6 0

3 years ago