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2 years ago

EVALUATE THE WORD PROBLEMS

1 answer:

7 0

Another effective strategy for helping students improve their mathematics performance is related to solving word problems. More specifically, it involves teaching students how to identify word problem types based on a given problem’s underlying structure, or schema. Before learning about this strategy, however, it is helpful to understand why many students struggle with word problems in the first place.

Difficulty with Word Problems

Most students, especially those with mathematics difficulties and disabilities, have trouble solving word problems. This is in large part because word problems require students to:

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Which number is largest? A. 0.78 B. 3/10 C. 0.50 D. 82/100

Olegator [25]

C. 0.50.

I believe that is the answer. Hope this helped! Sorry if I’m wrong.

-Bella :)

7 0

3 years ago

Read 2 more answers

The price of tickets for the dance was 1 ticket for $6 or 2 tickets for $8 she looked inside the cash box and found $200 and tic

Aleks04 [339]

We can say that exchanging one couple's ticket for an individual's ticket would increase the money in the cash box from 200 to 202 and it would result in an even number of couples tickets sold.

Step-by-step explanation:

Let the number of tickets sold to the individuals = s

Let the number of tickets sold to the couples = c

According to the question,

s + c = 46 ( Equation 1)

Since each individual's ticket is $6, the total amount of money made by selling tickets to individuals is 6s.

Similarly, since each ticket sold to couples is $8, the total amount of money made by selling tickets to couples is 8c.

So,

6 s + 8 c = 200 ( Equation 2)

On solving both the equations, we get

c = 38 and s = 8

Therefore, 8 tickets were sold to individuals and 38 tickets were sold to the couples.

5 0

2 years ago

Please help and give me an explanation I don’t understand or know if it’s correct

andrezito [222]

Hello :) we got similar answers but i believe you made a few distributing mistakes! hopefully my work makes sense, if not i’ll totally try to explain more

p.s i might be too late whoops

p.p.s i’m in a higher grade but i haven’t done this kinda math in a longgg time haha so if you think i did something wrong trust your gut ✌️

7 0

2 years ago

The sum of rational number and an irrational number

Angelina_Jolie [31]

Answer:

The sum of a rational number and an irrational number is irrational." By definition, an irrational number in decimal form goes on forever without repeating (a non-repeating, non-terminating decimal). By definition, a rational number in decimal form either terminates or repeats.

Step-by-step explanation:

However, if the irrational parts of the numbers have a zero sum (cancel each other out), the sum will be rational. "The product of two irrational numbers is SOMETIMES irrational." Each time they assume the sum is rational; however, upon rearranging the terms of their equation, they get a contradiction (that an irrational number is equal to a rational number). Since the assumption that the sum of a rational and irrational number is rational leads to a contradiction, the sum must be irrational.

5 0

3 years ago

Se quiere construir un muro de 4 m de alto, 12 m de largo y 10 cm de espesor. ¿Cuántos ladrillos de 8 cm de alto, 20 cm de largo

Llana [10]

Answer:

3000

Step-by-step explanation:

Let's start by finding the volume of the wall. The volumen of the wall can be considered as the volume of a rectangular prism. The volume of a rectangular prism is given by:

$V_w=w*l*h\\\\Where:\\\\w=Width=10cm=0.1m\\l=Length=12m\\h=Height=4m$

So the volume of the wall is:

$V_w=0.1*12*4=4.8m^3$

Now, we can find the volume of the brick using the same method since a brick can be considered as a rectangular prism as well:

$V_b=w*l*h\\\\For\hspace{3}the\hspace{3}brick\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m$

Hence:

$V_b=(0.1)*(0.2)*(0.08)=0.0016m^3$

In order to know how many bricks are required to build the wall, we just need to fill the wall volume with the number of bricks of this volume. So:

$V_w=nV_b\\\\Where\\\\n=Number\hspace{3}of\hspace{3}bricks$

Solving for n:

$n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000$

Therefore, we need 3000 bricks to build that wall.

Translation:

Comencemos por encontrar el volumen del muro. El volumen del muro puede considerarse como el volumen de un prisma rectangular. El volumen de un prisma rectangular viene dado por:

$V_w=w*l*h\\\\Donde:\\\\w=Espesor=10cm=0.1m\\l=Largo=12m\\h=Alto=4m$

Entonces el volumen del muro es:

$V_w=0.1*12*4=4.8m^3$

Ahora, podemos encontrar el volumen del ladrillo utilizando el mismo método, ya que un ladrillo también puede considerarse como un prisma rectangular:

$V_b=w*l*h\\\\Para\hspace{3}el\hspace{3}ladrillo\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m$

Por lo tanto:

$V_b=(0.1)*(0.2)*(0.08)=0.0016m^3$

Para saber cuántos ladrillos se requieren para construir el muro, solo necesitamos llenar el volumen del muro con la cantidad de ladrillos de este volumen. Entonces:

$V_w=nV_b\\\\Donde\\\\n=Numero\hspace{3}de\hspace{3}ladrillos$

Resolviendo para n:

$n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000$

Por lo tanto, necesitamos 3000 ladrillos para construir ese muro.

4 0

3 years ago