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Roman55 [17]
3 years ago
5

Consider the function f(x) = x2 and the function g(x) shown below. How will the graph of g(x) differ from the graph of f(x)? g(x

) = 4·f(x) = 4x2
Mathematics
1 answer:
Lapatulllka [165]3 years ago
6 0

Answer:

The graph of g of x would be more narrow then f of x.

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Part A Prove that when x > 1, a triangle with side lengths a = x2 − 1, b = 2x, and c = x2 + 1 is a right triangle. Use the Py
Nataly [62]

Step-by-step explanation:

Given : A triangle with side lengths a = x^2-1, b = 2x, \text{ and } c = x^2 + 1

To find : Prove that when x > 1, it is a right triangle. Use the Pythagorean theorem and the given side lengths to create an equation. Use the equation to show that this triangle follows the rule describing right triangles. Explain your steps ?

Solution :

For right triangle the Pythagorean theorem is to be satisfied.

i.e. c^2=a^2+b^2

Here, a = x^2-1, b = 2x, \text{ and } c = x^2 + 1

Substitute the values,

(x^2+1)^2=(x^2-1)^2+(2x)^2

x^4+1+2x^2=x^4+1-2x^2+4x^2

x^4+1+2x^2=x^4+1+2x^2

LHS=RHS

It is a right triangle.

7 0
4 years ago
What 2 numbers add to -3 and multiply to 2
serg [7]
We need to look at factors of 2, which are only 2 and 1... How do we get them to add to -3? Well, they have to be negative.

-2 + -1 = -3

What about the multiplication? A negative × a negative = a positive, so

-2 × -1 = 2

So your answer is

-2 and -1
6 0
4 years ago
PLZ HELP LAST QUESTION
marshall27 [118]
The pictures confused me, can you explain them please?
4 0
3 years ago
Help me find the volume please
Elena L [17]

Answer:

<h2>V = 605 in³</h2>

Step-by-step explanation:

The formula of a volume of a pyramid:

V=\dfrac{1}{3}BH

B - area of a base

H - height

We have the square in the base with side length a = 11 in.

Area of a base:

B=11^2=121\ in^2

Calculate the volume:

V=\dfrac{1}{3\!\!\!\!\diagup_1}(121)(15\!\!\!\!\!\diagup^5)=(1)(121)(5)=605\ in^3

3 0
3 years ago
A homeowner is installing a swimming pool in his backyard. he want its length to be 4 feet longer than its width. then he wants
marishachu [46]
1. You have that:

 - The homeowner<span> want the length of the swimming pool to be 4 feet longer than its width.</span> 
 - He wants to surround it with a concrete walkway 3 feet wide.
 - He can only afford 300 square feet of concrete for the walkway.

 2. Therefore, the tota area is:

 At=L2xW2

 L2 is the lenght of the walkway (L2=L1+3+3⇒L2=(W1+4+6)⇒L2=W1+10).
 W2 is the width of the walkway (W1+3+3⇒W2=W1+6)

 3. The area of the walkway is:

 A2=At-A1

 A2=300 ft²

 4. Therefore, you have that the width of the swimming pool is:

 A2=(W1+10)(W1+6)-(W1+4)(W1)
 300=(W1²+6W1+10W1+60)-(W1²+4W1)
 W1²+16W1+60-W1²-4W1-300=0
 12W1-240=0
 W1=240/12
 W1=20 ft

 5. And the length is:

 L1=W1+4
 L1=20+4
 L1=24 ft
8 0
3 years ago
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