Answer:
please add the attachment of this question
Answer:
5.76 km/h
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relationship between angles and sides of a right triangle. Here, we are given the side opposite the angle (angle of depression), and we want to find the adjacent side (distance from shore).
Tan = Opposite/Adjacent
tan(4°) = (height of tower)/(distance from shore)
tan(4°) = (50 m)/(distance from shore)
Then the distance from shore is ...
distance from shore = (50 m)/tan(4°) ≈ 715.03 m
__
At the second sighting, the distance from shore is ...
distance from shore = (50 m)/tan(12°) ≈ 235.23 m
So, the distance traveled in 1/12 hour is ...
715.03 m - 235.23 m = 479.80 m
and the speed in km per hour is ...
speed = 0.4798 km/(1/12 h) = 5.7576 km/h
The speed of the boat is about 5.76 km per hour.
= $ 32,275.00
Equation:
A = P(1 + rt)
Calculation:
First, converting R percent to r a decimal
r = R/100 = 4.85%/100 = 0.0485 per year,
putting time into years for simplicity,
24 quarters ÷ 4 quarters/year = 6 years,
then, solving our equation
A = 25000(1 + (0.0485 × 6)) = 32275
A = $ 32,275.00
The total amount accrued, principal plus interest,
from simple interest on a principal of $ 25,000.00
at a rate of 4.85% per year
for 6 years (24 quarters) is $ 32,275.00.
By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
<h3>How to solve a system of equations</h3>
In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:
x - y = 5 (1)
x² · y = 5 · x + 6 (2)
By (1):
y = x + 5
By substituting on (2):
x² · (x + 5) = 5 · x + 6
x³ + 5 · x² - 5 · x - 6 = 0
(x + 5.693) · (x - 1.430) · (x + 0.737) = 0
There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737
And the y-values are found by evaluating on (1):
y = x + 5
x₁ ≈ 5.693
y₁ ≈ 10.693
x₂ ≈ 1.430
y₂ ≈ 6.430
x₃ ≈ - 0.737
y₃ ≈ 4.263
By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
To learn more on nonlinear equations: brainly.com/question/20242917
#SPJ1
Aimme is right. All the sides are obtuse. They do not equal exactly 90 degrees.
