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3 years ago

For the story, select an equation that describes the relationship between the two quantities.

Mathematics

2 answers:

NemiM [27]3 years ago

6 0

Answer:

hope this helps

Step-by-step explanation:

1 i believe because its the only one that says "more than". The other two say less than.

SVETLANKA909090 [29]3 years ago

3 0

Answer:

Step-by-step explanation:

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Find out the answers to this

meriva

Answer:

$\tan \theta = - \frac{1}{5} = - 0.2$

$\cos \theta = 0.98$

$\sin \theta = - 0.196$

Step-by-step explanation:

It is given that $\cot \theta = - 5$ and $\theta$ is in the fourth quadrant.

So, only $\cos \theta$ will have positive value and $\sin \theta$ , $\tan \theta$ will have negative value.

Now, $\cot \theta = - 5$

⇒ $\tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5}$ (Answer)

We know, that $\sec^{2} \theta - \tan^{2} \theta = 1$

⇒ $\sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019$

{Since, $\cos \theta$ is positive then $\sec \theta$ will also be positive}

⇒ $\cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98$ (Answer)

We know, that $\csc^{2} \theta - \cot^{2} \theta = 1$

⇒ $\csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099$

{Since, $\sin \theta$ is negative then $\csc \theta$ will also be negative}

⇒ $\sin \theta = \frac{1}{\csc \theta} = \frac{1}{- 5.099} = - 0.196$ (Answer)

4 0

3 years ago

I think I'm getting better. But just in case I still don't understand , what are decimals?

vagabundo [1.1K]

Decimals are a number and a dot and more numbers

8 0

2 years ago

Read 2 more answers

A gift box is a rectangular prism. The box measure 8 inches by 10 inches by 3 inches. What is it’s surface area?

MakcuM [25]

Answer:

the answer is 80 i think

Step-by-step explanation:

bc dependng on 2lw+2lh+2hw, formula 8 and 10 would be length and width

Lets say

8=width

10=lenght

3in=height

u would do

2 x l x w + 2 x l h + 2 x h x w=

2 x 10 x 8 + 2 x 10 x 3 + 3 x 8=

160 + 60 + 48+=

268 is the sa

pls brainliest and more points :0

8 0

3 years ago

PLEASE HELP QUICKLY 25 POINTS

Natalija [7]

Answer:

○ $\displaystyle \pi$

Step-by-step explanation:

$\displaystyle \boxed{y = 3sin\:(2x + \frac{\pi}{2})} \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{4}} \hookrightarrow \frac{-\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3$

OR

$\displaystyle \boxed{y = 3cos\:2x} \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3$

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of $\displaystyle y = 3sin\:2x,$ in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted $\displaystyle \frac{\pi}{4}\:unit$ to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD $\displaystyle \frac{\pi}{4}\:unit,$ which means the C-term will be negative, and by perfourming your calculations, you will arrive at $\displaystyle \boxed{-\frac{\pi}{4}} = \frac{-\frac{\pi}{2}}{2}.$ So, the sine graph of the cosine graph, accourding to the horisontal shift, is $\displaystyle y = 3sin\:(2x + \frac{\pi}{2}).$ Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit $\displaystyle [-1\frac{3}{4}\pi, 0],$ from there to $\displaystyle [-\frac{3}{4}\pi, 0],$ they are obviously $\displaystyle \pi\:units$ apart, telling you that the period of the graph is $\displaystyle \pi.$ Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at $\displaystyle y = 0,$ in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.