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Luba_88 [7]
3 years ago
13

Please help!!solve using Pythagorean theorem to solve for x​

Mathematics
1 answer:
swat323 years ago
8 0

Answer

the answer is 24

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I need help can someone please help me ​
Vladimir [108]

Answer:

1a)

5 green circles

1 green square

2 red circles

4 red circles

1b) probability is 5/12

Step-by-step explanation:

count for each (1a)

count every shape=12

since there is 5 green circles

the probability is 5/12

8 0
4 years ago
Mercado is 37 years old. His age is 5 years more than four times his daughter's age. How old is his daughter?
hichkok12 [17]
So,

Let Mercado's age be m and his daughter's age be d.

Our first equation: m = 37

Our second equation: m = 5 + 4d

Substitute 37 for m
37 = 5 + 4d

Subtract 5 from both sides
32 = 4d

Divide both sides by 4
8 = d

His daughter is 8 years old.
8 0
3 years ago
Read 2 more answers
Which could be the first step in solving the equation represented by the model below? HELP PLZ
kotegsom [21]

Answer:

take away four from both -4

5 0
3 years ago
Read 2 more answers
. A patio is built in the shape of a trapezoid, as shown. Determine the area of the patio.
netineya [11]

Answer:

84 in²

Step-by-step explanation:

(15+6)0.5 * 8 = 21(0.5) * 8 = 10.5 * 8 = 84

8 0
3 years ago
Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl
Salsk061 [2.6K]
So to find the answer you need to use SOHCAHTOA 
Sine= Opposite/ Adjacent
Cosine= Adjacent/Hypotenuse
Tan = opposite/adjacent

angle ADC is 60 so to find the length of line ABC we would use the angle and the line DC. 
We would use Tan with opposite over adjacent
Tan 60 = opp. / 5 root 3 
opp. = 15 
so that is the length of the entire thing, all you need to do now is find the length of the single line of BC which we can use the same equation with just Tan 30 now.
Tan 30 = opp. / 5 root 3 
opp. = 5 
next you need to take the entire ABC length and subtract the length of BC to get AB
15-5 = 10 
so the answer would be C
8 0
3 years ago
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