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expeople1 [14]
3 years ago
8

How many feet does a car travelling at 65 MPH go in one second ?

Mathematics
2 answers:
Semenov [28]3 years ago
4 0

Answer:

At 65 mph, keeping one second of following distance means the vehicle is traveling 100 feet behind the vehicle in front. It takes an automobile a minimum of 150 feet to stop. With a 100 foot gap plus the auto's stopping distance of 150 feet, an impact would occur within 250 feet.

Gala2k [10]3 years ago
3 0

Answer: At 65 mph, keeping one second of following distance means the vehicle is traveling 100 feet behind the vehicle in front. It takes an automobile a minimum of 150 feet to stop. With a 100 foot gap plus the auto's stopping distance of 150 feet, an impact would occur within 250 feet.

Step-by-step explanation:

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The length of a rectangle is 7 more than the width. The area is 744 square centimeters. Find the length and width of the rectang
horsena [70]

Answer:

the width of the rectangle is 24 centimeters and the length is 31 centimeters.

Step-by-step explanation:

We first have to write an equation for this, but let's just recall that the area of a rectangle is equal to the length times the width. A=L×W.

A is the area

L is the length

W is the width.

So, for our equation we can start out by putting that 744= ? times ?.

So, we are given that the length is 7 more than the width. We are going to have to translate that to represent the length.

We need a variable. Let's use the letter "W," the width of the rectangle.

W=W.

The length is 7 more than the width, so it is L=W+7.

Length represents the W+7

Width represents W.

Now, we can complete our equation.

744=W(W+7).

Simplify the expression.

744=W^{2}+7W.

Alright, you may be thinking on how we are going to solve this problem. This equation correlates with quadratic functions.

Let's complete the square.

In a quadratic function, the standard from is y=ax^{2} +bx+c.

We need to find the c value.

We can do this by applying a formula. The formula states that c= b/2 and the whole thing squared. In other words, (\frac{b}{2} )^{2}.

In this case, the b value is 7.

square 7, which is 49 and square 2 which is 4.

Now, the c value is 49/4.

We have now just created a perfect square trinomial.

Not only do we add 49/4 to W squared plus 7W, we also add 49/4 to 744.

744 plus 49/4 is 756/25.

Now, we have W^{2}+7w+\frac{49}{4} = 756.25

Change W squared plus 7w plus 49/4 to a binomial squared.

Just take the square root of the a value, W, and 49/4 for c. the square root of W squared is W. the square root of 49/4 is 7/2.

Those values are to the power of 2.

In other words, (W+\frac{7}{2})^{2}  =756.25

To isolate for W, take the square root of both sides.The square root of W plus 7/2 squared is just W+7/2. The square root of 756.25 is 27.5

There are two solutions for W because square roots be positive or negative, but we are dealing with positive since negative doesn't make sense with the context of the problem.

We have W+3.5 or \frac{7}{2}=27.5

Isolate for W by subtracting both sides by 3.5 You get to W=24.

Therefore, the width of the rectangle is 24 centimeters.

Alright, we found the width. We now need to find the length. The problem stated that the rectangle was 7 more than the width. So, 24+7=31. Therefore, the length of the rectangle is 31 centimeters.

L=31cm

W=24cm.

I hope this was helpful! I wish you have an amazing day!

4 0
3 years ago
What’s the correct answer for this ?<br> The traffic light is approximately _____ feet tall
wlad13 [49]

Answer:

Height = 21.78 ft

Step-by-step explanation:

Tan θ = opposite / Adjacent

tan 40 = opposite / 20

where opposite is the part of the traffic light

0.839 × 20 = opposite

opposite = 16.78 ft

Now the total height of traffic light = 16.78 ft +5 ft

Total Height = 21.78 ft

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X = 2x + 57
x = the number of hours
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Artyom0805 [142]

Answer: (b) Provide hints on what the teacher thinks is important

Explanation: Clearly, the teacher selects what to ask in the tests, and it is plausible to think that (s)he will select problems that they deem important.

The teacher will know that students look at past tests, and so they will tend to change the wording and values in the tests to prevent plagiarism, so (a) is not the right choice.

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3 years ago
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