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KonstantinChe [14]

2 years ago

11

Combine any like terms in the expression. If there are no like terms, rewrite the expression. 8fg^2 + 7fg^2 – 2fg^2

2 answers:

AleksAgata [21]2 years ago

6 0

13fg^2
Hope this helps!

dlinn [17]2 years ago

5 0

13fg^2 I’m pretty sure this is the answer hope this helps

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In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

Integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y):

$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

4 0

3 years ago

Find the difference when the polynomial -5x^2+3x+8 is subtracted from the polynomial 2x^2+4x+1.

geniusboy [140]

The difference is $7x^{2} + 1x-7$ .

Step-by-step explanation:

Step 1:

The polynomial $-5x^{2}+3x+8$ is subtracted from the polynomial $2x^{2} + 4x +1$ .

If we write this as an equation, we get

$(2x^{2} + 4x +1) -(-5x^{2}+3x+8)$ .

To subtract the polynomials, we group up the terms based on their variables.

In this subtraction, there are two variables i.e. $x^{2}$ and $x$ and there is one constant term.

Step 2:

The subtraction of the $x^{2}$ variables; $2x^{2} -(-5x^{2} ) = 2x^{2} +5x^{2} = 7x^{2}$ .

The subtraction of the $x$ variables; $4x - (3x) = 1x$ .

The subtraction of the constants; $1-(8) = -7$ .

So $(2x^{2} + 4x +1) -(-5x^{2}+3x+8) = 7x^{2} + 1x-7$ .

4 0

2 years ago

Ava wants to ride her bicycle more than 75 miles this week. She has already ridden her bicycle 16 miles. Which inequality could

Roman55 [17]

It’s A)5m+16 75 your welcome and if it’s wrong I don’t know why

4 0

3 years ago

PLEASE HELP ME I NEED ANSWERS

kolezko [41]

70 is the area of the polygon

5 0

2 years ago

Pam jogged 15 and 3/4 miles in 3 hours. At this rate how long would it take Pam to jog 28 and 7/8 miles?

Lorico [155]

First, let’s find the distance Pam jogs in one hour.
15.75/3 = 5.25 mph.
Now, simply divide 28.875 (28 and decimal of 7/8) by our new rate.
28.875/5.25 = 5.5 hours. Choice B

3 0

2 years ago