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2 years ago

Take a factor out of the square root: 4√450

Mathematics

2 answers:

Sav [38]2 years ago

8 0

Answer:

60√2

Step-by-step explanation:

Factor the value 450

450 = 9 x 50 = 9 x 5 x 2

4√450 = $4\sqrt{9*25*2$

= $4*3*5\sqrt2$

= $60\sqrt2$

$60\sqrt2$

-Chetan K

igor_vitrenko [27]2 years ago

3 0

Following are the calculation to the square root:

Given:

$\bold{4 \sqrt{450}}$

To find:

square root=?

Solution:

Calculating the factor of 450:

$\to 450 = 9 \times 50 = 9 \times 5 \times 2 \\\\\to 4\sqrt{450} =4 \sqrt{ 9 \times 25 \times 2}\\\\$

$=4 \times 3 \times 5 \sqrt{2} \\\\ =60 \sqrt{2} \\\\$

Therefore, the final answer is " $60 \sqrt{2}$ ".

Learn more:

brainly.com/question/19795061

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3 years ago

A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses

Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = average age of the random sample of horses with colic = 12 yrs

$\mu$ = average age of all horses seen at the veterinary clinic = 10 yrs

$\sigma$ = standard deviation of all horses coming to the veterinary clinic = 8 yrs

n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( $\bar X$ $\geq$ 12)

P( $\bar X$ $\geq$ 12) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{12-10}{\frac{8}{\sqrt{60} } }$ ) = P(Z $\geq$ 1.94) = 1 - P(Z < 1.94)