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3 years ago

PLEASE HELP!!!

Mathematics

2 answers:

ElenaW [278]3 years ago

4 0

Answer:

Option B). Area of the rectangular region is 264 yd².

Step-by-step explanation:

It has been given in the question that a 68 yd of rope was used to rope off all four sides of a rectangular region.

Width of the region is 12 yd.

Since length of the rope is the perimeter of the rectangular region.

Therefore 2×(length + width) = 68

2(length + 12) = 68

2×length + 24 = 68

2×length = 68 - 24 = 44

Length = 44/2 = 22 yd

Therefore area of the rectangular region = 22×12 = 264 yd²

Option B) 264 yd² is the region.

SVETLANKA909090 [29]3 years ago

4 0

Answer:

answer is B i took a test on it

Step-by-step explanation:

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PolarNik [594]

Answer:

Step-by-step explanation:

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3 years ago

In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home. Give the value of th

astra-53 [7]

Answer:

The value of the standard error for the point estimate is of 0.0392.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home.

This means that $n = 100, p = \frac{81}{100} = 0.81$

Give the value of the standard error for the point estimate.

This is s. So

$s = \sqrt{\frac{0.81*0.19}{100}} = 0.0392$

The value of the standard error for the point estimate is of 0.0392.

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2 years ago