What’s the inverse function of
h(x)=2/x+1 ?
2 answers:
Answer:
h(x)=log2(x)
Step-by-step explanation:
The find the inverse of an invertible function y=f(x),
swap y and x and solve for y.
We have h(x)=y=2x.
Swapping x and y gives x=2y.
We now wish to solve for y.Take the log with base 2 of both sides of the equation to free the y variable.
x=2ylog2(x)=log2(2y)=yThus, y=h(x)=log2(x).
See that we used the fact that logn(nx)=x
Answer:
If I understand correctly, your trying to find the inverse function of:
h(x)= 
+ 1, If so...
Answer:
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