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3 years ago

What’s the inverse function of h(x)=2/x+1 ?

Mathematics

2 answers:

babymother [125]3 years ago

6 0

Answer:

h(x)=log2(x)

Step-by-step explanation:

The find the inverse of an invertible function y=f(x),

swap y and x and solve for y.

We have h(x)=y=2x.

Swapping x and y gives x=2y.
We now wish to solve for y.Take the log with base 2 of both sides of the equation to free the y variable.

x=2ylog2(x)=log2(2y)=yThus, y=h(x)=log2(x).
See that we used the fact that logn(nx)=x

Rasek [7]3 years ago

6 0

Answer:

If I understand correctly, your trying to find the inverse function of:

h(x)= $\frac{2}{x}$ + 1, If so...

Answer:

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