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Lena [83]
2 years ago
11

What is the length of the hypotenuse? If necessary, round to the nearest tenth.

Mathematics
2 answers:
Nana76 [90]2 years ago
8 0

<u>Answer:</u>

  • The length of the hypotenuse is 5 m.

<u>Step-by-step explanation:</u>

<em>We can solve for 'c' using Pythagoras theorem. Let's solve it.</em>

  • c² = 3² + 4²
  • => c² = 9 + 16
  • => c² = 25
  • => c = 5

Hence, the length of the hypotenuse is 5 m.

Hoped this helped.

BrainiacUser1357

belka [17]2 years ago
6 0

Answer:

C=5

Step-by-step explanation:

hope this helps

so sorry if this is the wrong answer

plz mark brainliest if correct answer

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nCx=\frac{n!}{(n-x)! x!}  

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P(X=7)

And using the probability mass function we got:

P(X=7)=(15C7)(0.23)^7 (1-0.23)^{15-7}=0.0271  

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To complete the identity, we need these fundamental identities:

1)\displaystyle{sec(x)=\frac{1}{cos(x)}

2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)

\displaystyle{csc(x)= \frac{1}{sin(x)}


Thus, by identity 1 we have:

\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}

by identity :

\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)

recall the values :

\displaystyle{ sin(\frac{ \pi }{2})^R=sin(90^o)=1\\\\

\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0, 


so: 

cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)=0+sin(\theta)=sin(\theta)


Putting all these together, we have:


\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}

which is equal to csc(\theta), by identity 3


Answer: D
7 0
3 years ago
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