Ask question

Ask question

All categories

2 years ago

11

What is the length of the hypotenuse? If necessary, round to the nearest tenth.

2 answers:

Nana76 [90]2 years ago

8 0

<u>Answer:</u>

The length of the hypotenuse is 5 m.

<u>Step-by-step explanation:</u>

<em>We can solve for 'c' using Pythagoras theorem. Let's solve it.</em>

c² = 3² + 4²
=> c² = 9 + 16
=> c² = 25
=> c = 5

Hence, the length of the hypotenuse is 5 m.

Hoped this helped.

$BrainiacUser1357$

belka [17]2 years ago

6 0

Answer:

C=5

Step-by-step explanation:

hope this helps

so sorry if this is the wrong answer

plz mark brainliest if correct answer

You might be interested in

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

Please explain thank you

mixas84 [53]

Okjhgfdfghjjhgfdfghjhgfdfghjsdfghjkhgfdsfghjrhrthrthtj

6 0

3 years ago

What's the correct answer and why?

alexandr402 [8]

3x^4 becomes 3(3x)^4=3*3^4*x^4
y^2 becomes (3y)^2=3^2y²
the new z=3² the old z, so b is correct.

4 0

3 years ago

I need an Answer Immediately pls!!!!!!!!!

Salsk061 [2.6K]

Answer:

2,033-993.50= 1039.50/74.25= 14

Step-by-step explanation:

not sure the exact equation but p would be 14 and you'd do something similar to that shown above

8 0

3 years ago

Find the measure of angle x. A) 90° B) 45° C) 135° D) 180°

tiny-mole [99]

The angles of a triangle always equal 180.

You do 180 - 80 - 45. X = 45.

8 0

3 years ago