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2 years ago

Shonda goes to a restaurant with no more than $15 to spend. She buys a burger that costs

Mathematics

1 answer:

andrew11 [14]2 years ago

5 0

Answer:

she has 4.5

and she should´ve got bacon egg and cheese than that burger

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Which values of m and b will create a system of equations with no solution? Check all that apply.

Law Incorporation [45]

Answer:

y = -2x + 1

Step-by-step explanation:

Then any equation of the form y = -2x + b, b≠1 will create a system with no solution. Hence the values of m and b are m = -2, b ≠ 1.

hope i helped

8 0

3 years ago

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Suppose that is in standard position and the given point is on the terminal side of 0. Give the exact value of the indicated tri

Lilit [14]

Answer:

12/13

Step-by-step explanation:

The length of the segment from the origin to the terminal point is ...

r = √((-5)² +12²) = √169 = 13

The sine of the angle is the ratio of the y-coordinate to this distance

sin(θ) = y/r = 12/13

_____

Additional comment

The other trig functions are ...

cos(θ) = x/r = -5/13

tan(θ) = y/x = -12/5

This is a 2nd-quadrant angle, where the sine is positive, but the cosine and tangent are negative.

6 0

2 years ago

Complete the statement to explain why 8,000 divided by 800 = 10

ddd [48]

Because when you multiply by 10, it adds a zero to the end of the number, like 12*10 = 120, so vise versa for dividing

7 0

3 years ago

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Pls giys just anser this question I just need help and this app is for helping so please write it no files ok because I know it’

Naya [18.7K]

Answer:

please can I get the full picture I can't fully understand

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2 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

4 0

2 years ago