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timurjin [86]
2 years ago
11

Juno is taking a taxi. The table represents a linear function and shows the amount she owed after various numbers of miles trave

led. Is the rate of change 2. 25? Amount Juno Owed for a Taxi Miles Amount Owed (dollars) 1 2. 5 2 2004. 75 3 7 4 9. 25 5 11. 5 Yes, because the amount owed changes by 1 every time the miles change by 2. 25. Yes, because the amount owed changes by 2. 25 every time the miles change by 1. No, because the amount owed does not change by 1 every time the miles change by 2. 25. No, because the amount owed does not change by 2. 25 every time the miles change by 1.
Mathematics
1 answer:
fenix001 [56]2 years ago
8 0

Linear functions are represented by constant rates.

The true statement is (d) No, because the amount owed does not change by 2.25 every time the miles change by 1.

From the table, we can see that:

As the number of miles increase by 1, the amount owed increases, but it does not increase at a constant rate of 2.25.

This means that, the table does not represent a linear function.

Represent the linear functions at:

brainly.com/question/15602982

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Answer:

(a) The critical number of f(x) are x=-4, 1

(b)

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Step-by-step explanation:

(a) The critical numbers of a function are given by finding the roots of the first derivative of the function or the values where the first derivative does not exist. Since the function is a polynomial, its domain and the domain of its derivatives is (-\infty, \infty). Thus:

\frac{df(x)}{dx}  = \frac{d(2x^3+9x^2-24x)}{dx} =6 x^2+18x -24\\6 x^2+18x -24=0\\\boxed{x=-4, x=1}

(b)

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Combining  the domain (-\infty, \infty) with the critical numbers we have the intervals (-\infty, -4), (-4, 1) and (1, \infty). Note that any of the points are included, in the case of the infinity it is by definition and the critical number are never included because the function monotony is not defined in the critical points, i.e. it is not monotone increasing or decreasing. Now, let's check for the monotony in each interval, for this, we check for the sign of the first derivative in each interval. Evaluating in each interval the first derivative (one point is enough), we obtain the monotony of the function to be:

  • Increasing for (-\infty, -4)
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(c) From the values obtained in (a) so the relative extremum are the points (-4, 112) and (1, -13). The y-values are found by evaluating the critical numbers in the original function. Since the first derivative decreases after passing through  x=-4 and increases after passing through the point x=1 we have:

  • relative maximum (-4, 112)
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