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Nataly_w [17]
3 years ago
11

Write a description of the rule (X, Y) (x+8,y+6)

Mathematics
1 answer:
Dafna11 [192]3 years ago
5 0

Answer:

You must add 8 to the x and 6 to the y.

Step-by-step explanation:

(x+8,y+6)

    \/

x+8 & y+6

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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Seven students, A, B, C, D, E, F, and G, have been selected to be possible characters in a school play. Only 4 people will actua
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if you pick G you don't have to pick D so I didn't I picked B so that I could pick E and they didn't say any rules about F so I picked G,B,E,F

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Write the slope-intercept form of the equation of each line. Identify the slopes y-intercept WILL GIVE BRAINIEST
slega [8]

Answer:

9) slope= (-1/5) y-intercept is 1   equation is y=-1/5x+1

11) slope= (-1/5) y-intercept is -4   equation is y=-1/5x-4

13) slope= (-4)  y-intercept is 5   equation is y=-4x+5

Step-by-step explanation:

hope this helps :3

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3 years ago
Find GCF of 28y^5, and 6300x
Marianna [84]
225
hope it helps :))))
4 0
2 years ago
For the angle 0 = 150° moving counter-clockwise in standard position, determine which
Kitty [74]

Answer: Start at the positive

x

-axis, then rotate left by the desired angle.

Explanation-

Standard position means the first arm of the angle is the positive

x

-axis, and the other arm is placed by rotating counter-clockwise from there, by the amount of the angle.

As a basic example, the symbol

∠

is about a 45° angle in standard position.

To get a feel for where the second arm (called the "terminal arm") will go, remind yourself that the axes themselves meet each other at 90°.

If our angle was 90°, the terminal arm would be on the positive

y

-axis.

If our angle was 180°, it would be on the negative

x

-axis.

Wait! 180° is more than 150°, so our angle is somewhere in quadrant 2. In fact, 150° is 2/3 of the way between 90° and 180°, so our terminal arm will be 2/3 of the way into quadrant 2.

graph{(y+tan(pi/6)x)(y^2-.00001x)=0 [-10, 10, -5, 5]}

(ignore the part of the line in quadrant 4)

8 0
3 years ago
Lin decides to solve the equation using the quadratic formula. Here is her work: xxx=−b±b2−4ac−−−−−−−√2a=−(−6)±(−6)2−4(1)(10)−−−
Sedbober [7]

Answer:

x = 3 + i\ or\ x = 3 - i

Step-by-step explanation:

Given

x = \frac{-(-6) \± \sqrt{(-6)^2 - 4(1)(10)}}{2*1}

Required

Solve, in terms of i

We have:

x = \frac{-(-6) \± \sqrt{(-6)^2 - 4(1)(10)}}{2*1}

Solve the expressions in bracket

x = \frac{-(-6) \± \sqrt{36 - 40}}{2*1}

x = \frac{-(-6) \± \sqrt{-4}}{2}

Express -4 as 4 * -1

x = \frac{-(-6) \± \sqrt{-4*1}}{2}

Split

x = \frac{-(-6) \± \sqrt{4}*\sqrt{-1}}{2}

In complex numbers;

i = \sqrt{-1

So, we have:

x = \frac{-(-6) \± 2*i}{2}

x = \frac{6 \± 2i}{2}

Factorize

x = \frac{2(3 \± i)}{2}

x = 3 \± i

Split

x = 3 + i\ or\ x = 3 - i

7 0
3 years ago
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