Let us assume the first odd integer to be = x Then The consecutive middle odd integer = x + 2 The third consecutive odd integer = x + 4 So we can now write the equation as x + x + 2 + x + 4 = 5(x + 2) - 18 3x + 6 = 5x + 10 - 18 3x + 6 = 5x - 8 3x - 5x = - 8 - 6 - 2x = - 14 2x = 14 x = 14/2 = 7 So the first odd integer is 7 The second consecutive odd integer = (x + 2) = (7 + 2) = 9 The third consecutive odd integer = (x + 4) = 7 + 4) = 11 So the three consecutive odd integers are 7, 9, 11.
in the denominator is missing in the second expression. It should be
