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kirill [66]
2 years ago
10

Jerry’s loan had a principal of $22,000. He made quarterly payments of $640 for nine years until the loan was paid in full. Ho

w much did Jerry pay in interest? a. $3,120 b. $1,040 c. $2,010 d. $5,760.
Mathematics
1 answer:
vredina [299]2 years ago
3 0

The amount Jerry paid in interest is $1,040.

Given to us,

Jerry's principal amount = $ 22,000,

quarterly payment for each quarter = $ 640

Total time for which Jerry paid each quarter = 9 years

As We know that in a year there are 4 quarters,

so, \rm 1\ year = 4\ quarters,

\rm 9\ year = 9\times 4\ quarters,

9 years = 36 quarters,

The total amount paid by Jerry for nine years in each quarter =

quarterly payment for each quarter x no. of quarters for which amount paid

\rm Total\ amount\ paid\ by\ Jerry\ for\ nine\ years\ in\ each\ quarter = \$640\times 36 quarters = \$23,040

Thus, the total amount paid by Jerry for nine years in each quarter is $23,040.

Therefore,

\rm Amount\ Jerry\ pay\ in\ interest = Amount\ Jerry\ paid- Principal\ amount,

\rm Amount\ Jerry\ pay\ in\ interest = \$23,040-\$22,000 = \$1040

Hence, the amount Jerry paid in interest is $1,040.

To know more visit;

brainly.com/question/12522729

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Find the line through (3, 1, −2) that intersects and is perpendicular to the line x = −1 + t, y = −2 + t, z = −1 + t. (HINT: If
mel-nik [20]

Answer:

( xo , yo , zo ) = ( 1 , 0 , 1 )

Step-by-step explanation:

Given:-

- A line passing through point (3, 1, −2) intersects and is perpendicular to line with coordinates:

                  x = −1 + t, y = −2 + t, z = −1 + t   .... t = arbitrary parameter.

Find:-

The coordinates for point of intersection.

Solution:-

- The line that passes through point (3, 1, −2) = ( a, b , c ) and an a arbitrary point on the given line have the following direction vector d2 :

                 d2 = ( x2 , y2 , z2 )

                 x2 = a - ( x ) = 3 - ( -1 + t ) = 4 - t

                 y2 = b - ( y ) = 1 - ( -2 + t ) = 3 - t

                 z2 = c - ( z )  = -2 - ( -1 + t ) = -1 - t

                d2 = (  4 - t , 3 - t , -1 - t )

- The direction vector d1 of the given line is:

                 d1 = ( x1 , y1 , z1 )

                 x1 = 1

                 y1 = 1

                 z1 = 1

                 d1 = ( 1 , 1 , 1 )

- The dot product of two orthogonal vectors is always equal to zero:

                 d1.d2 = 0

                 (  4 - t , 3 - t , -1 - t ) . ( 1 , 1 , 1 ) = 0

- Solve for parameter (t):

                 (4 - t) + (3 - t) + (-1 - t) = 0

                  6 -3t = 0

                  t = 2  

- The coordinates of the point of intersections can be evaluated by substituting the value of "t" into the given equation of line:

                 xo ( t = 2) = - 1 + 2 = 1

                 yo ( t = 2) = - 2 + 2 = 0

                 zo ( t = 2) = - 1 + 2 = 1

- The coordinates are:

                 ( xo , yo , zo ) = ( 1 , 0 , 1 )

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Step-by-step explanation:

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Combine like terms

12x+1 = 12x +1

Subtract 12x from each side

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