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Oliga [24]
3 years ago
14

A rectangular cube of iron is a side 8 cm. What is it volume.​

Mathematics
1 answer:
Airida [17]3 years ago
5 0
  • A rectangular cube of iron is a side 8 cm.
  • Given, side (a) = 8 cm.
  • We know, volume of a cube =  {a}^{3}
  • Therefore, the volume

=  {8}^{3}  \:  \: cm ^{3}  \\  = 512 \:  \:  {cm}^{3}

<u>A</u><u>nswer</u><u>:</u>

<u>The </u><u>volume </u><u>is </u><u>5</u><u>1</u><u>2</u><u> </u><u>cube </u><u>centimetres</u><u>.</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

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How to find vertical and horizontal asymptotes of polynomials?
guajiro [1.7K]
Vertical asymptotes are when y tends to infinity, which in other words means you need a fraction where you're dividing by zero. So to find the vertical asymptotes, solve the denominator of the fraction and the solutions are the asymptotes since that is where it will be dividing by zero.

Horizontal asymptotes are the opposite and is where x tends to infinity -- This can be done by dividing through with the xs still there, since you are effectively just looking at multiples of infinity and infinity squared and so on. When you have an x to the power you can forget about all the other x's on the same half of the fraction, since infinity squared is infinitely bigger than infinity - yes it's abstract and a bit stupid I know.
If the degree of the polynomial on the denominator is larger than the numerator, there is an asymptote at y=0 (since the bottom becomes infinitely larger than the top). If it is lower than the numerator, you have to divide through by long division and you end up with an oblique asymptote i.e. an asymptote where the dotted line would follow a linear equation e.g. y=x

For example
f(x)= \frac{6x^2-3x+4}{2x^2-8}

The vertical asymptote can be found by solving 2x^2-8=0 i.e. x=+-2 so our vertical asymptotes are at 2 and -2.

The horizontal asymptote, think of all the x's as infinity. SInce there are x^2s, we dont need to worry about the numbers or the other x's
Therefore we are left with 6x^2/2x^2, which gives us 3. Therefore our horizontal asymptote would be at y=3.
7 0
3 years ago
Need help don’t understand
Arturiano [62]

Answer:

a) <EGA and <AGB

b) <FGE and <CGB

c) <FGE and <EGC

d) <FGE and <FGA

e) <CGD=55

Step-by-step explanation:

a) Supplementary angles add up to 180 degrees.

<EGA and <AGB are supplementary.

b) Vertical angles are also called X-angles. Think of them as angles in the vertically opposite corners of the letter X.

<FGE and <CGB are a pair of vertical angles

c) Adjacent angles are next to each other.

<FGE and <EGC are a pair of adjacent angles

d) Complementary angles add up to 90 degrees.

<FGE and <FGA are a pair of complementary angles

e) <CGD=<FGA because they are vertical angles.

But <EGA=90-35=55

Therefore <CGD=55

6 0
3 years ago
Compare and contrast supplementary and coneplementary angles
gladu [14]

Answer:


Step-by-step explanation :Two concepts that are related but not the same are supplementary angles and complementary angles. The difference is their sum. Supplementary angles are two angles whose measures sum to a 180 degrees and complementary are the sum have to add up to 90 degrees.


7 0
3 years ago
Read 2 more answers
A bridge constructed over a bayou has a supporting arch in the shape of an inverted parabola. Find the equation of the parabolic
Olegator [25]

Answer:

y = (-2/125)(x - 50)² + 40

Step-by-step explanation:

The total length of the bridge is 100 meters.

Maximum height always occurs at midpoint of x.

So for x=50 meters , y = 40 meters.

As the vertex is given at the maximum height,  Vertex can be defined at the point (50,40)

We know that the general equation for vertical parabola is:

y = a(x - h)² + k

Where (h,k) = Vertex = (50,40)

Substitute in the equation:

y = a(x - 50)² + 40 ⇒ Equation (i)

We know 2 more points on the parabola. We know that when x=0 , y=0 and we also know that when x=100m, y=0 meters.

Substitute any point in the above equation

Substituting (100,0) in the equation

0 = a(100 - 50)² +40

Solve the equation for a:

a = - 2/125

Substitute a in Equation (i)

y = (-2/125)(x - 50)² + 40

6 0
3 years ago
The side of a triangle is 10 square meters longer than the side of an equalateral triangle. The perimeter of the square is 3 tim
ryzh [129]
<span>square side = 10 meters
perimeter of square = 4*L = 40 meters
...
let side of triangle be x
perimeter of triangle = 3x

...
40 = 3x *3
9x =40
x= 40/9
x= 4.44 meters length of side of triangle</span>
5 0
3 years ago
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