Question

Suppose that 3. 33 g of acetone at 25. 0 °c condenses on the surface of a 44. 0-g block of aluminum that is initially at 25 °c. If the heat released during condensation goes only toward heating the metal, what is the final temperature (in °c) of the metal block?.

Answer 1

The final temperature on the block is 25 degrees.

Heat is a form of energy. This question shows that energy is transferred from the acetone to the metal block.

Data given;

• M1 = 3.33g
• T1 = 25 degrees
• M2 = 44g
• T2 = 25 degree
• C1 = 124.5 J mol K
• C2 = 0.89 J/g K

Heat Transfer

Applying the principles of heat transfer,

Heat loss = Heat gain

$m1c1(T1 - T3) = m2c2(T3 - T2)\\3.33*124.5*(25.0 - T3) = 44*0.89*(T3 - 25)\\10364.625 - 414.585T3 = 39.16T3 - 979\\10364.625+979 = 414.585T3 +39.16T3\\11343.25 = 453.745T3\\T3 = \frac{11343.25}{453.745} \\T3 = 24.999\\T3 = 25$

From the calculation above, the final temperature on the block is 25 degrees.

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