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Dmitry_Shevchenko [17]

2 years ago

7

suppose that an object is moving with constant nonzero acceleration. which of the following is an accurate statement concerning

its motion?

1 answer:

stiks02 [169]2 years ago

8 0

I know that if the acceleration isn't zero then the object has to be constantly slowing down or speeding up

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The ___________ was the center of many Middle Age European towns, often dwarfing the village or town itself. Question 4 options:

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Which one of these would have the strongest gravitational pull?

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Complete the proof given ab*be=cb*bd prove abc dbe.

vampirchik [111]

The complete proofs with all the reasons and statements; have been enumerated below

<h3>What are triangle proofs?</h3>

From the attached triangle, we can complete the proofs as follows;

Statement 1; AB * BE = CB * BD

Reason 1; Given

Statement 2; CB/BE = AB/BD

Reason 2; Property of Cross Multiplication

Statement 3; ∠ABC ≅ ∠DBE

Reason 3; Vertical Angles

Statement 4; ΔABC ~ ΔDBE

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2 years ago

Which of the following statements about urban growth is true?

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3 years ago

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The vertices of square cdef are c(1, 1), d(3, 1), e(3,−1) and f(1,−1). Which of the following shows that its diagonals are congr

maks197457 [2]

The equation $-1 = -\frac {1}{1}$ shows that the diagonals are congruent perpendicular bisectors.

The vertices of the square are given as:

c = (1,1)
d = (3,1)
e =(3,-1)
f = (1,-1)

<h3>How to determine the congruent perpendicular bisectors.</h3>

Start by calculating the slope of diagonal ce using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$m = \frac{-1-1}{3 -1}$

$m = \frac{-2}{2}$

$m_1 = -1$

Next, calculate the slope of diagonal df using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$m = \frac{-1-1}{1-3}$

$m = \frac{-2}{-2}$

$m_2 = 1$

The slopes of both diagonals are:

$m_1 = -1$

$m_2 = 1$

By comparing both slopes, we have:

$m_1 = -\frac {1}{m_2}$

i.e.

$-1 = -\frac {1}{1}$

Hence, $-1 = -\frac {1}{1}$ shows that the diagonals are congruent perpendicular bisectors.

Read more about perpendicular bisectors at:

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2 years ago