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Dmitry_Shevchenko [17]

3 years ago

7

suppose that an object is moving with constant nonzero acceleration. which of the following is an accurate statement concerning

its motion?

1 answer:

stiks02 [169]3 years ago

8 0

I know that if the acceleration isn't zero then the object has to be constantly slowing down or speeding up

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Find the values of k and b if it is known that the graph of y=kx b goes through points (2, 10) and (−7, −10).

andreev551 [17]

The values of k and b of this graph that passes through the given points is $k = \frac{20}{9}$ and $b = \frac{-50}{9}$

<u>Given the following points:</u>

Points on the x-axis = (2, -7)

Points on the y-axis = (10, -10)

$y = kx + b$ .....equation 1.

To find the values of k and b since the graph passes through the given points:

First of all, we would determine the slope of the graph passing through the given points.

$Slope. \;m = \frac{Change \; in \; y \;axis}{Change \; in \; x \;axis} \\\\Slope. \;m = \frac{y_2 - y_1}{x_2 - x_1}$

Substituting the points into the formula, we have;

$Slope. \;m = \frac{-10 - 10}{-7 - 2}\\\\Slope. \;m = \frac{-20}{-9}\\\\Slope. \;m = \frac{20}{9}$

The standard form of an equation of line is given by the formula;

$y = mx + b$ ....equation 2

<u>Where:</u>

x and y are the points.

m is the slope.

b is the intercept.

Next, we would determine the intercept of the graph:

$10 = \frac{20}{9}(2) + b\\\\10 = \frac{40}{9} + b\\\\b = \frac{40}{9} - 10\\\\b = \frac{40\; - \;90}{9}\\\\b = \frac{-50}{9}$

The standard form of this equation of line is:

$y = \frac{20}{9}x - \frac{50}{9}$ .....equation 3.

Comparing eqn 1 and eqn 3, we can deduce:

$k = \frac{20}{9}$ and $b = \frac{-50}{9}$

Therefore, the values of k and b of this graph that passes through the given points is $k = \frac{20}{9}$ and $b = \frac{-50}{9}$

Read more: brainly.com/question/18123312

3 0

3 years ago

A population of values has a normal distribution with μ = 21.9 μ = 21.9 and σ = 47.4 σ = 47.4 . You intend to draw a random samp

Gelneren [198K]

Answer:

Olá, boa tarde. Caso precise, estou a disposição para a realização de trabalhos acadêmicos, entre em contato comigo, Fernanda 21994321300

Explanation:

7 0

3 years ago

Una tractomula se desplaza con rapidez de 69 km/h. Cuando el conductor ve una vaca atravesada en medio de la carretera, acciona

irinina [24]

Responder:

El remolque del tractor no atropellará a la vaca.

Explicación:

Dado lo siguiente:

Velocidad del tractor remolque: 69 km / h

Tiempo necesario para detenerse después de aplicar los frenos = 4 segundos

Distancia de vacas desde el remolque del tractor = 25 metros

Por lo tanto, la distancia recorrida por el remolque del tractor después de aplicar los frenos:

Velocidad del tractor remolque / Tiempo

69 km / h = (69 * 1000) m / 3600s = 69000m / 3600s = 19.17m / s

(19,17 m / s ÷ 4 s) = 4,8 m

Como la distancia de la vaca está más lejos (25 m), el remolque del tractor no pasará por encima de las vacas

3 0

3 years ago

Suppose you need to verify how to correctly use commas. You open your English textbook and scan the chapter titles. In which one

Jlenok [28]

Answer:

D because it is involving the proper way to use commas

Explanation:

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Can any software work with any OS? Explain your answer with an example.

Sergio [31]

Answer:

CrossOver Linux 9 (code-named Snow Mallard) and its Mac brother, CrossOver Mac 9, let you run many popular Windows applications on Linux or Mac OS X.

Explanation:

5 0

3 years ago