3x + 2y + 6z = 5??
then
distance = |3(1) + 2(-2) + 6(4) - 5| / √(3^2 + 2^2 + 6^2)
the plane is ax + by + cz - d = 0 while the point is (x1, y1, z1)
I think that's the answer
Answer:
the answer is -16
Step-by-step explanation:
neagative 16
Answer:
Step-by-step explanation:
-2 x 14 = -28
b is the answer