Which table of values would produce the graph shown above?

Which statement about 3(x2 – 4) is true?

daser333 [38]

What are the different statements

5 0

3 years ago

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Simplify (tan(θ)+cot(θ))/(sec(θ)•csc(θ)) completely

AlekseyPX

$\dfrac{\tan\theta+\cot\theta}{\sec\theta\csc\theta}=\dfrac{\dfrac{\sin\theta}{\cos\theta}+\dfrac{\cos\theta}{\sin\theta}}{\dfrac1{\cos\theta}\dfrac1{\sin\theta}}=\dfrac{\sin^2\theta+\cos^2\theta}1=1$

6 0

3 years ago

What is the opposite of the opposite of any integer?

Pani-rosa [81]

<h2>The opposite of an opposite of a integer is the original integer.</h2>

8 0

2 years ago

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Explain how to use a horizontal number line<br> to order four fractions from least to greatest.

horsena [70]

Answer:

To order fractions from least to greatest, start by finding the lowest common denominator for all of the fractions. Next, convert each of the fractions by dividing the lowest common denominator by the denominator and then multiplying the top and bottom of the fraction by your answer.

Step-by-step explanation:

Solution for the above problem: We first find the least common denominator by finding the least common multiple for 4, 3, 2, 6, and 8. We find the LCM by the prime factorization method. Next, place the fractions in order from least to greatest.

4 0

3 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$