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Anestetic [448]
2 years ago
11

To find detailed information about the origin of an email message, look at the ________________.

Computers and Technology
1 answer:
Valentin [98]2 years ago
8 0
Email header. The email header is a code snippet in an HTML email, that contains information about the sender, recipient, email's route to get to the inbox and various authentication details
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In most programming languages, the compiler carries a preprocessing step to determine if certain statements will compile. For in
MakcuM [25]

Answer:

See explaination for program code

Explanation:

package com.company;

import java.io.IOException;

import java.nio.file.Files;

import java.nio.file.Paths;

import java.util.Stack;

/*

* A program which reads input from given text filename and prints

* whether it passed the pre-processing stage or not

* Sample input

* int A = (a + b);static void display(int x)

* {

* //A sample input file

* }

* */

public class MyPreprocessor {

/*

* Reads input from filename and returns a string

* containing whole text

* */

public String readInput(String filename) {

String content = "";

try {

content = new String(Files.readAllBytes(Paths.get(filename)));

} catch (IOException e) {

e.printStackTrace();

}

return content;

}

/**

* Filters input since we are only concerned with

* a subset of input = '{}[]()/*'

*/

public String filterText(String text) {

String output = "";

for(int i = 0;i<text.length();++i) {

switch (text.charAt(i)) {

case '[':

case ']':

case '{':

case '}':

case '(':

case ')':

case '*':

case '/':

output += text.charAt(i);

}

}

return output;

}

/*

* Uses stack to determine if input is valid or not

* */

public boolean parse(String input) {

Stack<Character> St = new Stack<Character>();

// '$' is special symbol to represent bottom of stack

St.push('$');

for(int i = 0;i<input.length();++i) {

Character symbol = input.charAt(i);

if(St.peek().equals(getOpenSymbol(symbol)))

St.pop();

else St.push(symbol);

}

return St.peek() == '$';

}

private static Character getOpenSymbol(Character symbol) {

switch (symbol) {

case '}': return '{';

case ']': return '[';

case ')': return '(';

case '*': return '*';

case '/': return '/';

default: return ' ';

}

}

public static void main(String[] args) {

MyPreprocessor preprocessor = new MyPreprocessor();

String inputText = preprocessor.readInput("src/input.txt");

String filteredInput = preprocessor.filterText(inputText);

if(preprocessor.parse(filteredInput))

System.out.println("preprocessing passed.");

else System.out.println("preprocessing failed!");

}

}

6 0
3 years ago
What will you better be prepared for by learning about the animals you photograph
krek1111 [17]

D. All of the above.

Makes the most sense! :3

6 0
3 years ago
What is the faster way for browsers to obtain the revocation status of a digital certificate attached to a Web site?
Lyrx [107]

Answer:

The fastest way to obtain the revocation status of digital certificate of the website is by using Online certificate Status Protocol (OSCP).

Explanation:

Online certificate status protocol is the protocol that help user to check and verify the digital certificate revocation status. This protocol is linked with the digital certificate issuance authority. Whenever someone want to verify the status of the digital certificate that is attached to access the website. The website administrator can send the request to OSCP handler to ensure the status of the certificate. The OSCP handler is connected through certificate issuance authority, send the detail to verify the status. After verifying the status, OSCP handler respond as certificate is valid or revoked to the concerned user.

5 0
3 years ago
What is one effective way for employees to keep their skill-sets current
natta225 [31]
Is it a multiple choice answer? if so would like to see the answers as there are TONS of effective ways and if i list one it may not be in that list you have if its multiple choice.
3 0
3 years ago
NEED HELP ON TEST!!!
Phoenix [80]

Answer:

1.  \: speaker \:  notes \\ 2. \: accessible

5 0
3 years ago
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