Answer:
⣠⣴⣶⣿⠿⢿⣶⣶⣦⣄⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⣼⡿⠋⠁⠀⠀⠀⢀⣈⠙⢿⣷⡄⠀⠀ ⠀⠀⠀⠀⢸⣿⠁⠀⢀⣴⣿⠿⠿⠿⠿⠿⢿⣷⣄⠀ ⠀⢀⣀⣠⣾⣿⡇⠀⣾⣿⡄⠀⠀⠀⠀⠀⠀⠀⠹⣧ ⣾⡿⠉⠉⣿⠀⡇⠀⠸⣿⡌⠓⠶⠤⣤⡤⠶⢚⣻⡟ . ⣿⣧⠖⠒⣿⡄⡇⠀⠀⠙⢿⣷⣶⣶⣶⣶⣶⢿⣿⠀ . ⣿⡇⠀⠀⣿⡇⢰⠀⠀⠀⠀⠈⠉⠉⠉⠁⠀⠀⣿⠀. ⣿⡇⠀⠀⣿⡇⠈⡄⠀⠀⠀⠀⠀⠀⠀⠀⢀⣿⣿⠀ ⣿⣷⠀⠀⣿⡇⠀⠘⠦⣄⣀⣀⣀⣀⣀⡤⠊⠀⣿⠀ ⢿⣿⣤⣀⣿⡇⠀⠀⠀⢀⣀⣉⡉⠁⣀⡀⠀⣾⡟⠀ ⠀⠉⠛⠛⣿⡇⠀⠀⠀⠀⣿⡟⣿⡟⠋⠀ * ° * • ☆ ° .°• * ✯ ☄ ☆ ★ * ° * °· * . • ° ★ • ☄ ☄ ▁▂▃▄▅▆▇▇▆▅▄▃▁
⣠⣴⣶⣿⠿⢿⣶⣶⣦⣄⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⣼⡿⠋⠁⠀⠀⠀⢀⣈⠙⢿⣷⡄⠀⠀ ⠀⠀⠀⠀⢸⣿⠁⠀⢀⣴⣿⠿⠿⠿⠿⠿⢿⣷⣄⠀ ⠀⢀⣀⣠⣾⣿⡇⠀⣾⣿⡄⠀⠀⠀⠀⠀⠀⠀⠹⣧ ⣾⡿⠉⠉⣿⠀⡇⠀⠸⣿⡌⠓⠶⠤⣤⡤⠶⢚⣻⡟ . ⣿⣧⠖⠒⣿⡄⡇⠀⠀⠙⢿⣷⣶⣶⣶⣶⣶⢿⣿⠀ . ⣿⡇⠀⠀⣿⡇⢰⠀⠀⠀⠀⠈⠉⠉⠉⠁⠀⠀⣿⠀. ⣿⡇⠀⠀⣿⡇⠈⡄⠀⠀⠀⠀⠀⠀⠀⠀⢀⣿⣿⠀ ⣿⣷⠀⠀⣿⡇⠀⠘⠦⣄⣀⣀⣀⣀⣀⡤⠊⠀⣿⠀ ⢿⣿⣤⣀⣿⡇⠀⠀⠀⢀⣀⣉⡉⠁⣀⡀⠀⣾⡟⠀ ⠀⠉⠛⠛⣿⡇⠀⠀⠀⠀⣿⡟⣿⡟⠋⠀ * ° * • ☆ ° .°• * ✯ ☄ ☆ ★ * ° * °· * . • ° ★ • ☄ ☄ ▁▂▃▄▅▆▇▇▆▅▄▃▁
f(x) = x² - 8x + 3
y = x² - 8x + 3
- 3 - 3
y - 3 = x² - 8x + 16
y - 3 + 16 = x² - 8x + 16
y + 13 = x² - 8x + 16
y + 13 = (x - 4)²
- 13 - 13
y = (x - 4)² - 13
f(x) = (x - 4)² - 13
The equation would be x+3x(10+2x)=142
The sides are 22cm , 54cm and 66 cm.
Since A and B are the midpoints of ML and NP, we can say that AB is parallel to MN and LP. In order to find ∠PQN, we can work with the triangles PQB and NQB. According to SAS (Side-Angle-Side) principle, these triangles are congruent. BQ is a common side for these triangles and NB=BP and the angle between those sides is 90°, i.e, ∠NBQ=∠PBQ=90°. After finding that these triangles are equal, we can say that ∠BNQ is 45°. From here, we easily find <span>∠PQN. It is 180 - (</span>∠QNP + ∠NPQ) = 180 - 90 = 90°
Answer:
15°
Step-by-step explanation:
sum of exterior angles=360°
each angle=360/24=15°
b
20 ×n=360
n=360/20=18
18 sides
c.
(n-2)×180=174n
180n-174n=360
6 n=360
n=360/6=60
number of sides =60
