v + m = 32 and v = 5 + 2m are the equations that are used to determine m, the number of stuffed animals Mariposa has
Number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23
<h3>
<u>Solution:</u></h3>
Let "v" be the number of stuffed animals with Veronica
Let "m" be the number of stuffed animals with Mariposa
Given that,
Together, they have 32 stuffed animals
Therefore,
v + m = 32 --------- eqn 1
Veronica has 5 more than double the number of stutted animals as her friend Mariposa
Therefore,
Number of stuffed animals with Veronica = 5 + 2(number of stuffed animals with Mariposa)
v = 5 + 2m ---------- eqn 2
Thus eqn 1 and eqn 2 can be used to determine m, the number of stuffed animals Mariposa has
Let us solve eqn 1 and eqn 2
Substitute eqn 2 in eqn 1
5 + 2m + m = 32
5 + 3m = 32
3m = 32 - 5
3m = 27
<h3>m = 9</h3>
Substitute m = 9 in eqn 2
v = 5 + 2(9)
v = 5 + 18
<h3>v = 23</h3>
Thus number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23
Six tenths, one half, two fifths
The simplest interpretation would go a little something like this:
We know that we want the total donation amount to be more than $7,900, so we can set up this inequality to begin with

Where
D is the total donations raised (in dollars). How do we find D? Well, we just add up the total number of table reservations sold and the total number of single tickets sold. If we let
r stand for the number of reservation tickets and
s stand for the number of single tickets, then we have

So, the inequality representing this situation would be

And that would probably be fine for this problem.
<span><em>Footnote:</em>
</span>Of course, if this were a real-life scenario, we'd need to take some additional details into account: How many tables do we have? How many people can be seated at each table?
It depend upon what you roll it could be 6 because there are 6 faces are the dice
I’m going to go with Exponential