Answer: 1. I will bring my umbrella.
2. You work 20 hours a week, and you make $175.00.
Step-by-step explanation:
We know that a conditional statement "If p then q", is an if-then statement in which p is a hypothesis and q is a conclusion.
Now, for the given conditional statement "If it rains, then I will bring my umbrella. "
Here, q=" I will bring my umbrella." Therefore, the conclusion is "I will bring my umbrella".
For the next conditional statement "If you work 20 hours a week, then you make $125.00."
The statement "You work 20 hours a week, and you make $175.00." is false, because $175 is false conclusion here for the same hypothesis.
Factorization involves representing an expression with smaller terms.
- <em>When the greatest common factor is factored out, the equivalent expression is: </em>
<em>.</em> - <em>The complete factored expression is: </em>
<em />
The expression is given as:
The GCF of 
and 
is 
.
So, we have:
Factor out
To factorize the expression completely, we express 
and 
as squares.
So, we have:
Apply difference of two squares
So, the complete factor of is
Read more about factorization at:
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The function g(x)=4(x+3)² - 68 is mapped to 32.
<h3>What is equation?</h3>
An equation is a mathematical expression in terms of one or more unknown variable.
Given are the following functions:
f(x)= - 3x² - 4
g(x)= 4(x+3)²-68
f(x)= 3x
f(x)= 2x-62
To get the mapped function, we substitute the value of x in all function,
a) f(x)=-3x²- 4
Put x=2,
f(2)= -3 (2)² - 4
f(2)= -16
It is not mapped.
b) g(x)=4(x+3)² - 68
Put x=2,
g(2) = 4(2+3)² - 68
g(x) =32
It is mapped to 32.
c) f(x)=3x
Put x=2,
f(2) = 3 x 2 =6
It is not mapped.
d) f(x)=2x - 62
Put x=2,
f(2) =2x2 -62
f(2) = -58
It is not mapped.
Therefore, the function g(x)=4(x+3)² - 68 is mapped to 32.
Learn more about equations.
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The function, as presented here, is ambiguous in terms of what's being deivded by what. For the sake of example, I will assume that you meant
3x+5a
<span> f(x)= ------------
</span> x^2-a^2
You are saying that the derivative of this function is 0 when x=12. Let's differentiate f(x) with respect to x and then let x = 12:
(x^2-a^2)(3) -(3x+5a)(2x)
f '(x) = ------------------------------------- = 0 when x = 12
[x^2-a^2]^2
(144-a^2)(3) - (36+5a)(24)
------------------------------------ = 0
[ ]^2
Simplifying,
(144-a^2) - 8(36+5a) = 0
144 - a^2 - 288 - 40a = 0
This can be rewritten as a quadratic in standard form:
-a^2 - 40a - 144 = 0, or a^2 + 40a + 144 = 0.
Solve for a by completing the square:
a^2 + 40a + 20^2 - 20^2 + 144 = 0
(a+20)^2 = 400 - 144 = 156
Then a+20 = sqrt[6(26)] = sqrt[6(2)(13)] = 4(3)(13)= 2sqrt(39)
Finally, a = -20 plus or minus 2sqrt(39)
You must check both answers by subst. into the original equation. Only if the result(s) is(are) true is your solution (value of a) correct.
