Answer:
Capacity of tank = 44,000 l
Step-by-step explanation:
Given:
Height of tank = 3.5 m
Radius = 2 m
Find:
Capacity of tank
Computation:
Volume of cylinder = πr²h
Volume of cylinder = (22/7)(2)²(3.5)
Volume of cylinder = 44 m³
1m³ = 1000 l
So,
Capacity of tank = 44 x 1,000
Capacity of tank = 44,000 l
Answer:
c
Step-by-step explanation:
*View attached graph*
Firstly,
thanks for posting this.
81 = 9x9 or 9 squared so at this stage I'm guessing the last two.
x^ 8 = (x^ 4) x (x^ 2) (its called the multiplication rule of indices).
Okay I have approx 14 mins to answer.
No panic
√ 81.x^8 x <span>√ y^5
</span>√ (9x^2 x 9x^6) x <span>√ y^5
</span>= 9x x <span>√ 9x^6 x </span><span>√ y^5
</span>did I just gain time?
√ 9x^6 = <span>√ </span>3x ^3 x <span>√ 3x ^ 3
</span>or 2 . √ 3x^3. <span>√ y^5
</span>more time
okay, so that wasnt successful.
√ 9x^6 =<span>√ </span> (3x^2) x <span>√ </span>(3x^4)
Answer:
Step-by-step explanation:
let's break down 2,000,000 into its multiples,
Multiples of 2,000,000= 2⁷ × 5⁶
Using above values to find different combinations of length(l) and breadth (b) of rectangle and corresponding parameter of rectangle
- l=5, b=400,000 ,parameter= 2(5) + 2(400,000)= 800,010, total length of fence required= parameter+ side with shortest length= 800,015
- l=2 b=1,000,000 parameter= 2,000,004, shortest fence required= 2,000,008
- l=4, b= 500,000 parameter= 1,000,008, shortest fence required= 1,000,012
- From above, we can see a trend that the parameter of rectangle decreases if length and breadth are increased provided that area is constant. So, a rectangle will have shortest parameter if all of its sides are equal.
- length of side of rectangle with shortest possible parameter= 2^3 ×5^3= 1000 and breadth of side of rectangle with shortest possible parameter= 2^4× 5^3=2000
- Shortest possible length of fence= 2(2000)+2(1000)+1000=7000ft
