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musickatia [10]
3 years ago
10

Bacteria can multiply at an alarming rate when each bacteria splits into two new cells, thus doubling. If we start with only one

bacteria which can double every hour, how many bacteria will we have by the end of the day? Show your work
Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

2^24 = 16,777,216 bacterias.

Step-by-step explanation:

So we start with 1 bacteria

after 1 hours: 2*1 = 2

after 2 hours: 2*2 = 2^2 = 4

after 3 hours: 2*2^2 = 2^3  

after n hours: 2^n  

Since one day has 24 hours we have n = 24 and total number of bacteria will

be:  2^24 = 16,777,216 bacterias.

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A square has a side of 6.25 feet. What is the area in square feet? Round to the correct significant digits.
Hunter-Best [27]

The solution to this question is 39.0625.

This is because you will need to multiply the width by height. As this is in square feet it will be irrespective of which two sides we choose.

The calculation that will need to be done is the following :

6.25ft X 6.25ft which will equal 39.0625.

6.25 has three significant digits so rounding 39.0625 off to three significant digits is 39.1 square feet

7 0
3 years ago
The diameter of a wheel of a lorry is 150cm. If the lorry travels 376.8m, how many times does the wheel rotate?
tresset_1 [31]
<h3>Answer:  79 full rotations</h3>

====================================================

Explanation:

150 cm = 150/100 = 1.5 m

The wheel has a diameter of 1.5 meters

The circumference of the wheel is

C = pi*d

C = pi*1.5

C = 1.5pi

C = 4.71238898038469

I'm using my calculator's stored version of pi to get the most accuracy.

Then we divide the 376.8 over the circumference found

(376.8)/(4.71238898038469) = 79.9594434093682

Despite being very close to 80, we must round down to 79 because we don't have enough to get that full 80th rotation. In other words, we have 79 full rotations and then some change leftover.

Though for the sake of simplicity, I can see how it's useful to say "about 80 rotations" if 79 seems a bit clunky. I'll stick with 79 however. Let me know if your teacher instructs otherwise.

4 0
2 years ago
During a concert, $3280 was received. A total of 760 people attended. Reserved seats were $6 and general admission seats were $4
Andre45 [30]

Answer:

The number of reserved seat is 120 and number of general seat is 640.

Step-by-step explanation:

Given,

Total number of seats = 760

Total collected Money = $3280

Solution,

Let the total number of reserved seat be x.

And  the total number of general seat be y

Hence total number of seats is the sum of total number of reserved seat and  the total number of general seats.

So the equation can be written as;

x+y=760\ \ \ \ equation\ 1

Again, total money collected is the sum of fees of one reserved seat times total number of reserved seat and fees of one general seat times the total number of general seats.

So the equation can be written as;

6x+4y=3280\ \ \ \ \ equation\ 2

Now, multiplying equation 1 by 4 and then subtract it from equation 2.

4x+4y=3040

(6x+4y)-(4x+4y)=3280-3040\\\\2x=240\\\\x=\frac{240}{2}=120

On substituting the value of x in equation 1, we get;

x+y=760\\120+y=760\\y=760-120=640

Thus the number of reserved seat is 120 and number of general seat is 640.

8 0
3 years ago
To practice for a competition, Carly swam 0.51 kilometer in the pool each day for 3 weeks. How many meters did Carly swim in tho
erica [24]

Answer:

0.51km × 1000 = 510m

510m × (3×7) = 510m × 21 = 10710m in whole

Step-by-step explanation:

first we transform km to m (multiply by 1000)

then we count how much days are in three weeks ( 3 weeks × 7 days)

then we just multiply the meters per day × the days

99% it's true

7 0
3 years ago
How do I find a2 and a3 for the following geometric sequence? 54, a2, a3, 128
vlada-n [284]
The formula for the nth term of a geometric sequence:
a_n=a_1 \times r^{n-1}
a₁ - the first term, r - the common ratio

54, a_2, a_3, 128 \\ \\&#10;a_1=54 \\&#10;a_4=128 \\ \\&#10;a_n=a_1 \times r^{n-1} \\&#10;a_4=a_1 \times r^3 \\&#10;128=54 \times r^3 \\&#10;\frac{128}{54}=r^3 \\ \frac{128 \div 2}{54 \div 2}=r^3 \\&#10;\frac{64}{27}=r^3 \\&#10;\sqrt[3]{\frac{64}{27}}=\sqrt[3]{r^3} \\&#10;\frac{\sqrt[3]{64}}{\sqrt[3]{27}}=r \\&#10;r=\frac{4}{3}

a_2=a_1 \times r= 54 \times \frac{4}{3}=18 \times 4=72 \\&#10;a_3=a_2 \times r=72 \times \frac{4}{3}=24 \times 4=96 \\ \\&#10;\boxed{a_2=72, a_3=96}
7 0
3 years ago
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